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 01132011, 03:34 PM #1Member
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Find the second largest number in the array
I have written the following code for finding the 1st largest number in the given array and please do correct me in case there is some error in the program and can any one help me in finding the 2nd largest number in the array.
The code which i have written is as follows:
public class Assignment1 {
public static void main(String args[]) {
int i;
int temp = 95;
int arr[] = {95, 20, 34, 100, 9,150};
for (i = 0; i < arr.length  1; i++) {
if (i == 0) {
temp = arr[i];
} else if (temp < arr[i]) {
temp = arr[i];
}
}
System.out.println("Largest is :" + temp);
}
}
 01132011, 03:39 PM #2Senior Member
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Hi  have you tested your code? If so, and if it works correctly, you can do a second pass through the array to find the second largest number, using some if statements like you have done.
Also, are you not allowed to sort the array?
Best,user0
 01132011, 03:48 PM #3Senior Member
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Hi  also, looks like you are missing the last element in your loop, due to the condition arr.length  1. I would suggest changing the for loop to :
Java Code:for(int i = 0; i < arr.length; i++)
Java Code:int temp = Integer.MIN_VALUE;
best,user0
 01132011, 03:48 PM #4Member
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My code works .I am not able to write the code to find the second highest number.Any help or suggestions
 01132011, 04:09 PM #5
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One loop and a couple of ifstatements can do the job: think of it, suppose you have two numbers: first and second representing the largest and second largest numbers so far; also suppose a current number curr. If curr is larger or equal to first, what to do? Else, if curr is larger or equal to second, what to do?
kind regards,
Joscenosillicaphobia: the fear for an empty beer glass
 01132011, 05:08 PM #6Member
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