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Thread: complete sequence
 12282010, 05:34 PM #21Senior Member
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you mean what r the conditions that render a sequence incomplete...
if so they are:
 there is a number greater than n  1 // where n is the length of the sequence
 not all numbers between 1 and n  1 are found as differences
 when there is a number between 1 and n  1 that is repeated more than once
EDIT: Well i got it right finally
I added another for loop with an if statement in it that check the array diff in all of its elements if it has equal elements to return false
heres the code
Java Code:import java.util.*; import java.io.*; public class test { public static void main (String[] args) throws FileNotFoundException { Scanner input = new Scanner (new File(args[0])); int n; int end; Boolean status = false; while (input.hasNextLine()) { n = input.nextInt(); end = n  1; int [] array = new int [n]; int [] diff = new int [n1]; for ( int i = 0; i < n; i++) { array [i] = input.nextInt(); } for ( int j = 0; j < n  1; j++) { diff [j] = Math.abs(array[j]  array[j + 1]); } for ( int k = 0; k < n  1; k++) { if ( diff [k] >= 1 && diff [k] <= end ) { status = true; }else{ status = false; break; } } if ( array.length == 1) status = true; [B]for ( int p = 0; p < n  2; p++) { if ( diff [p] == diff [p + 1]) status = false; }[/B] if (status == true ) { System.out.println("Complete Sequence"); }else{ System.out.println("Not Complete Sequence"); } } } }
Last edited by aizen92; 12282010 at 05:41 PM.
 12282010, 06:24 PM #22
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[QUOTE=aizen92;166331]you mean what r the conditions that render a sequence incomplete...
if so they are:
 there is a number greater than n  1 // where n is the length of the sequence
 not all numbers between 1 and n  1 are found as differences
 when there is a number between 1 and n  1 that is repeated more than once
Isn't that a complicated way of saying: a sequence of n numbers has to be the a permutations of the numbers m, m+1, m+2 ... m+n1 for m <= 0?
kind regards,
JosThe only person who got everything done by Friday was Robinson Crusoe.
 12282010, 10:22 PM #23Senior Member
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I want to add something
I want to make sure that n is not greater than 3000
so i added this if statement after having n get the nextInt() the following statement
Java Code:if ( n >= 3000 ) { System.out.println("Your sequence is greater than 3000 elements"); break; }
 12292010, 07:12 AM #24Moderator
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You could try something like:
Java Code:while (input.hasNextLine()) { n = input.nextInt(); if(n >= 3000) { System.out.println("Message"); input.nextLine(); // read the line and throw it away continue; } end = n  1; int [] array = new int [n]; int [] diff = new int [n1]; // etc as before }
Already the method is becoming quite long. You should think about using separate methods each doing just one thing.
 12292010, 08:37 AM #25Senior Member
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Ok, it did the trick
thnx very much pbrockway2
 12292010, 12:58 PM #26Moderator
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