Getting an error

Hello friends I have a very fundamental doubt. You see, I just recently started taking java seriously. Currently I am into core java.

I have a doubt regarding access modifiers- public, private, protected, default.

Now what I have understood from reading the java textbook is that any class member will have one of these 4 access modifiers.

Example for this Code-
//Case1//
=====

try
{
BufferedImage originalImage = ImageIO.read(new File("C:\\Users\\PROTIK\\Desktop\\ReferenceProgram \\paper.jpg"));
int type = originalImage.getType() == 0? BufferedImage.TYPE_INT_ARGB : originalImage.getType();
BufferedImage resizeImageJpg = resizeImage(originalImage, type);
ImageIO.write(resizeImageJpg, "jpg", new File("C:\\Users\\PROTIK\\Desktop\\ReferenceProgram \\paper_resize.jpg"));
}

can also be written as
//Case2//
=====

try
{
default BufferedImage originalImage = ImageIO.read(new File("C:\\Users\\PROTIK\\Desktop\\ReferenceProgram \\paper.jpg"));
default int type = originalImage.getType() == 0? BufferedImage.TYPE_INT_ARGB : originalImage.getType();
default BufferedImage resizeImageJpg = resizeImage(originalImage, type);
ImageIO.write(resizeImageJpg, "jpg", new File("C:\\Users\\PROTIK\\Desktop\\ReferenceProgram \\paper_resize.jpg"));
}


But whenever I am trying to write the code in Case 2 type, by mentioning the access modifiers of the class members I am getting a compile time error. The error is "illegal start of exception".

Please somebody explain this to me??????

Quote:

---

Originally Posted by krashh205

try
{
default BufferedImage originalImage = ImageIO.read(new File("C:\\Users\\PROTIK\\Desktop\\ReferenceProgram \\paper.jpg"));
default int type = originalImage.getType() == 0? BufferedImage.TYPE_INT_ARGB : originalImage.getType();
default BufferedImage resizeImageJpg = resizeImage(originalImage, type);
ImageIO.write(resizeImageJpg, "jpg", new File("C:\\Users\\PROTIK\\Desktop\\ReferenceProgram \\paper_resize.jpg"));
}

---

'default' is a keyword used as a case selector in a switch statement. The default access specifier has no keyword, i.e. you can do:

Code:

---

private int foo;
protected in bar;
public int baz;
int foobar;

---

The last variable has a default (i.e. no explicit) access specifier.

kind regards,

Jos

And access modifiers are for instance variables (fields) and methods of a class, not for local variables within methods.

-Gary-

Oh, and for classes themselves, of course.

-Gary-

Thanks!!! That was helpful