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Thread: Pascals Triangle
 12092010, 10:53 PM #1Senior Member
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 12102010, 01:13 AM #2
Work it out on paper. Pick a number (like 5 or 6), and draw every line of Pascal's Triangle up to that point. Then think about how you determined each line in your head. Think about the criteria you use to determine which numbers would go in which order.
 12102010, 03:48 AM #3Senior Member
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Or to help out those who do not know post a description of what Pascal's Triangles are...so we can help you programmatically (is that a word :D)
 12102010, 06:37 AM #4
Silly guynever took math!? =) Clicky.
The numbers are based on binomial theorem; it is formulated as such, and procedurally generated by adding adjacent numbers for the row below.
 12102010, 06:10 PM #5Senior Member
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Hey guys thanks for the responses i've been away so i couldnt reply..UGGHH.. ok so i've wrote a little bit of code but im basically shooting in the dark ..heres what i have so far..Code has some english in it so please dont critique TOO MUCH , im trying.
Java Code:public class Pascal { public static void main(String[] args) { Pascal p=new Pascal(); int row=10; for(int x=0;x<=row;x++){ for(int y=0;y<=x;y++){ System.out.print(p.pascal(x, y)+" "); System.out.println(); } } } int pascal(int x,int y) { if(x=1  x=y  y=0){ } else{ return pascal(x1,y1)+pascal(x1,y); } } } //int x=row; //int y=col;
 12102010, 07:57 PM #6
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Suppose you have the values for n1, say, 1, 3, 3, 1. For the values for row n all you have to do is add all (left) consecutive values from the right: 1, 4, 6, 4 and add another value 1 to the right: 1, 4, 6, 4, 1. For n == 0 you have the value 1 and you don't need to know more.
kind regards,
JosThe only person who got everything done by Friday was Robinson Crusoe.
 12162010, 01:22 AM #7Senior Member
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