binary

Hello:)
how can i convert from decimal to binary in n-bits
that user can enter or limit n
example
the number is 3
n=4
by binary=0011......
???
thanks

My attempts

Code:

---

System.out.println("Enter your number");
    number=sc.nextInt();
    String bin=Integer.toBinaryString(number);
    System.out.println(bin);

---

but i cant compelet:o

Quote:

---

Originally Posted by Engineer

My attempts

Code:

---

System.out.println("Enter your number");
    number=sc.nextInt();
    String bin=Integer.toBinaryString(number);
    System.out.println(bin);

---

but i cant compelet:o

---

Well make clear what you want ..... By the way I just modified your code a bit ..... see if it is useful ...

Code:

---

      System.out.println("Enter your number");
      int number=sc.nextInt();
      System.out.println("Enter your limit");
      int limit=sc.nextInt();
      String bin=Integer.toBinaryString(number);
      if(bin.length()>limit){
          bin =  bin.substring(0, limit);
      }
      System.out.println(bin);

---

:p

Happy Coding ...

warm regards
Vinod M

Quote:

---

Originally Posted by Vinod Mukundan

Well make clear what you want ..... By the way I just modified your code a bit ..... see if it is useful ...

Code:

---

      System.out.println("Enter your number");
      int number=sc.nextInt();
      System.out.println("Enter your limit");
      int limit=sc.nextInt();
      String bin=Integer.toBinaryString(number);
      if(bin.length()>limit){
          bin =  bin.substring(0, limit);
      }
      System.out.println(bin);

---

:p

Happy Coding ...

warm regards
Vinod M

---

thank you for help:)
i use your code this is result:
Enter your number
3
Enter your limit
4
11
i dont mean that
i mean that it is
0011 not 11:o
i dont understand

Code:

---

bin =  bin.substring(0, limit);

---

thanks

Enter your number
3
Enter your limit
6

ok so wat will this should give you ???

Integer.toBinaryString(3); will give you 11 .... so wat u want is if the limit is 4 then we should add two 0's in front ??? is that it or ?

Quote:

---

Originally Posted by Vinod Mukundan

Enter your number
3
Enter your limit
6

ok so wat will this should give you ???

---

it give me
000011

Quote:

---

Originally Posted by Vinod Mukundan

Enter your number
3
Enter your limit
6

ok so wat will this should give you ???

Integer.toBinaryString(3); will give you 11 .... so wat u want is if the limit is 4 then we should add two 0's in front ??? is that it or ?

---

yes, iwant to make the number by limit
Ex:
limit=8
the number=5
binary=00000101

Code:

---

System.out.println("Enter your number");
        int number = sc.nextInt();
        System.out.println("Enter your limit");
        int limit = sc.nextInt();
        String bin = Integer.toBinaryString(number);
        if (bin.length() < limit) {
            while (bin.length() != limit) {
                bin = "0" + bin;
            }
        }
        System.out.println(bin);
    }

---

try this

Quote:

---

Originally Posted by Vinod Mukundan

Code:

---

System.out.println("Enter your number");
        int number = sc.nextInt();
        System.out.println("Enter your limit");
        int limit = sc.nextInt();
        String bin = Integer.toBinaryString(number);
        if (bin.length() < limit) {
            while (bin.length() != limit) {
                bin = "0" + bin;
            }
        }
        System.out.println(bin);
    }

---

try this

---

yes:)
thanks alot thats what i want:):)

Code:

---

System.out.println("Enter your number");
        int number = sc.nextInt();
        System.out.println("Enter your limit");
        int limit = sc.nextInt();
        StringBuilder sb = new StringBuilder();
        String bin = Integer.toBinaryString(number);
        for (int i = bin.length(); i < limit; i++) {
                sb.append("0");
        }
        sb.append(bin);
        System.out.println(sb.toString());
    }

---

Well use this one ... as String is immutable its better to use the builder instead...

ofcourse if you give 5 and limit 2 it will still print 101 ... do u need to overcome that also ?? try it

Happy Coding ..

warm regards
Vinod M

Quote:

---

Originally Posted by Vinod Mukundan

Code:

---

System.out.println("Enter your number");
        int number = sc.nextInt();
        System.out.println("Enter your limit");
        int limit = sc.nextInt();
        StringBuilder sb = new StringBuilder();
        String bin = Integer.toBinaryString(number);
        for (int i = bin.length(); i < limit; i++) {
                sb.append("0");
        }
        sb.append(bin);
        System.out.println(sb.toString());
    }

---

Well use this one ... as String is immutable its better to use the builder instead...

ofcourse if you give 5 and limit 2 it will still print 101 ... do u need to overcome that also ?? try it

Happy Coding ..

warm regards
Vinod M

---

thanks.................:)
i have aquestion
if i want to add to binary number
and the result in limit bits as number
how can i delete the carry end?????????????
and know that if its 1or0?????

Quote:

---

Originally Posted by Engineer

thanks.................:)
i have aquestion
if i want to add to binary number
and the result in limit bits as number
how can i delete the carry end?????????????
and know that if its 1or0?????

---

Can you give an example for the same ....... coz am a very lazy guy ... :p

Quote:

---

Originally Posted by Vinod Mukundan

Can you give an example for the same ....... coz am a very lazy guy ... :p

---

hhhhhhhhhhhhhh:)
ok,
if i have
0011
+
1011
----------
10110
i need to know if the first element (0) or (1), in this example(0)
but in the program how can i know that???????????
in the program if the first element==0...........yes
else no??????????
and how i can delete the last element(1)???

my attempets
put the number in array to know addressesfor the first number or last
but failed:o:o

Quote:

---

i need to know if the first element (0) or (1), in this example(0)
but in the program how can i know that???????????

---

Try

Code:

---

            if(bin.endsWith("0")) {
            }else{
          }

---

By the way u r reading string in ----> or <------ direction coz as far as i look the first element is 1 in the output 10110

Quote:

---

and how i can delete the last element(1)???

---

you mean just the last element or delete to a particular length ???

last element

Quote:

---

Originally Posted by Engineer

last element

---

and wat about the direction i asked in previous post :p


ok as far as I guess u need to limit the output .Check the below and lemme knw if u need anymore clarification

Code:

---


          if(bin.endsWith("0")) {
                    //Do watever you want to do if its 0
          }else{
          }

          if(bin.length()>limit) {
          bin = bin.substring(bin.length()-limit, bin.length());
        }

---

IF you just want the first element replace limit with 1 :) an yeah take out the if condition

thanks alot .............
how i know the last number i delet?????????
and print it alone???????????

Quote:

---

Originally Posted by Engineer

0011
+
1011
----------
10110

---

That is a severely broken ALU.

kind regards,

Jos

Quote:

---

Originally Posted by Engineer

thanks alot .............
how i know the last number i delet?????????
and print it alone???????????

---

By last number you mean 1 out of 1010 ??? then jus try

bin.charAt(0);