reversing a string

[toad]

I have written this program to check a palindrome.

import javax.swing.JOptionPane;

public class Exercise8_2 {
public static void main(String[] args) {
// Prompt the user to enter a string
String s = JOptionPane.showInputDialog(
null, "Enter a string:",
"Exercise8_2 Input", JOptionPane.QUESTION_MESSAGE);

if (isPalindrome(s)) {
System.out.println(s + " is a palindrome");
}
else {
System.out.println(s + " is not a palindrome");
}
}

/** Check if a string is a palindrome */
public static boolean isPalindrome(String s) {
// The index of the first character in the string
int low = 0;

// The index of the last character in the string
int high = s.length() - 1;

while (low < high) {
if (s.charAt(low) != s.charAt(high))
return false; // Not a palindrome

low++;
high--;
}

return true; // The string is a palindrome
}
}

I now need to rewrite this using a new string that is a reversal of the string and compare the two to determine whether the string is a palindrome. My reverse method needs to use the following header:

public static String reverse(String s)


Thanks for your help. The first part came pretty easy but the reversal is throwing me for a loop.

[JavaBean]

Create a new String object and append each character of the second String to the new one. A for loop starting from the last character of the first string going towards its beginning is enough. Check substring() method of String class to get one character at each step of your loop.

[hiranya]

Hi,

Check this out

	public String reverse(String s)
	{
		char[] array=s.toCharArray();
		String result="";
		for (int i=array.length-1; i>=0; i--)
		{
			result+=array[i];
		}
		return result;
	}

Regards,
Hiranya

[assamhammad]

may God bless u all

[JavaBean]

assamhammad, please stop posting this kind of (out of topic) messages. you already have 4 of this type of message out of your 7 posts in the last hour. This is called spam..

[bar311]

check this one....

public static String reverse(String s) {
   return (new StringBuffer(s)).reverse().toString();
}