How to create a zip out file from the current directory of input files

[renu]

Hi

The code is written using the IDE eclipse.
The errors i get are as follows :-
Exception in thread "main" java.lang.Error: Unresolved compilation problem:
The constructor ZipEntry(File) is undefined

at Zip.Zip.main(Zip.java:33)

package Zip;

import java.io.*;
import java.util.zip.*;

public class Zip {
   static final int BUFFER = 2048;
   public static void main (String argv[]) {
      try {
         BufferedInputStream origin = null;
         FileOutputStream dest = new FileOutputStream("C:\\Documents and Settings\\abc\\myzip.zip");         
         ZipOutputStream out = new ZipOutputStream(new BufferedOutputStream(dest));            
         //out.setMethod(ZipOutputStream.DEFLATED);
         byte data[] = new byte[BUFFER];
         //get the list of files from the given path.
         File folder = new File("C:\\Documents and Settings\\abc\\Local Settings\\Temp\\ABCD\\Data");
         File[] listOfFiles = folder.listFiles();

         for (int i = 0; i < listOfFiles.length; i++) {                
           FileInputStream fi = new FileInputStream(listOfFiles[i]);              
            origin = new BufferedInputStream(fi, BUFFER);  
            // Add ZIP entry to output stream.
            out.putNextEntry(new ZipEntry(listOfFiles[i]));      ------------------------------------------------->This line is pointed as error .... Any help is appreciated . 
            int count;
            while((count = origin.read(data, 0,BUFFER)) != -1) {              
               out.write(data, 0, count);
            }
            origin.close();
         }//end of for loop
         out.close();
      } catch(Exception e) {
         e.printStackTrace();
      }
   }
}

Thank You In Advance .

[renu]

Hi

The code is written using the IDE eclipse.The purpose of this program is to create a zip file ....of all the input files
The errors i get are as follows :-
Exception in thread "main" java.lang.Error: Unresolved compilation problem:
The constructor ZipEntry(File) is undefined

at Zip.Zip.main(Zip.java:33)

package Zip;

import java.io.*;
import java.util.zip.*;

public class Zip {
   static final int BUFFER = 2048;
   public static void main (String argv[]) {
      try {
         BufferedInputStream origin = null;
         FileOutputStream dest = new FileOutputStream("C:\\Documents and Settings\\abc\\myzip.zip");         
         ZipOutputStream out = new ZipOutputStream(new BufferedOutputStream(dest));            
         //out.setMethod(ZipOutputStream.DEFLATED);
         byte data[] = new byte[BUFFER];
         //get the list of files from the given path.
         File folder = new File("C:\\Documents and Settings\\abc\\Local Settings\\Temp\\ABCD\\Data");
         File[] listOfFiles = folder.listFiles();

         for (int i = 0; i < listOfFiles.length; i++) {                
           FileInputStream fi = new FileInputStream(listOfFiles[i]);              
            origin = new BufferedInputStream(fi, BUFFER);  
            // Add ZIP entry to output stream.
            out.putNextEntry(new ZipEntry(listOfFiles[i]));      ------------------------------------------------->This line is pointed as error .... Any help is appreciated . 
            int count;
            while((count = origin.read(data, 0,BUFFER)) != -1) {              
               out.write(data, 0, count);
            }
            origin.close();
         }//end of for loop
         out.close();
      } catch(Exception e) {
         e.printStackTrace();
      }
   }
}

Thank You In Advance

[Tolls]

What constructors does ZipEntry have.
Have you looked at the API to see?

[renu]

Sir

i did see the APIs for ZipEntry

Constructor Summary
ZipEntry(String name)
Creates a new zip entry with the specified name.
ZipEntry(ZipEntry e)
Creates a new zip entry with fields taken from the specified zip entry.


How do i change the code ....to add the constructor and make it run.

Pls help me solve this problem .

[Tolls]

You're not providng it either a String or a ZipEntry are you, you're providing it a File.
SO you need to figure out what you can use in File that makes sense to supply to the constructor.

[ypg]

Not very sure about the logic here, but probably go ahead with adding the filename to the ZipEntry Constructor.
ZipEntry(listOfFiles[i].getName())