How to create a zip out file from the current directory of input files

Hi

The code is written using the IDE eclipse.
The errors i get are as follows :-
Exception in thread "main" java.lang.Error: Unresolved compilation problem:
The constructor ZipEntry(File) is undefined

at Zip.Zip.main(Zip.java:33)

Code:

---

package Zip;

import java.io.*;
import java.util.zip.*;

public class Zip {
  static final int BUFFER = 2048;
  public static void main (String argv[]) {
      try {
        BufferedInputStream origin = null;
        FileOutputStream dest = new FileOutputStream("C:\\Documents and Settings\\abc\\myzip.zip");       
        ZipOutputStream out = new ZipOutputStream(new BufferedOutputStream(dest));           
        //out.setMethod(ZipOutputStream.DEFLATED);
        byte data[] = new byte[BUFFER];
        //get the list of files from the given path.
        File folder = new File("C:\\Documents and Settings\\abc\\Local Settings\\Temp\\ABCD\\Data");
        File[] listOfFiles = folder.listFiles();

        for (int i = 0; i < listOfFiles.length; i++) {               
          FileInputStream fi = new FileInputStream(listOfFiles[i]);             
            origin = new BufferedInputStream(fi, BUFFER); 
            // Add ZIP entry to output stream.
            out.putNextEntry(new ZipEntry(listOfFiles[i]));      ------------------------------------------------->This line is pointed as error .... Any help is appreciated .
            int count;
            while((count = origin.read(data, 0,BUFFER)) != -1) {             
              out.write(data, 0, count);
            }
            origin.close();
        }//end of for loop
        out.close();
      } catch(Exception e) {
        e.printStackTrace();
      }
  }
}

---

Thank You In Advance .

Hi

The code is written using the IDE eclipse.The purpose of this program is to create a zip file ....of all the input files
The errors i get are as follows :-
Exception in thread "main" java.lang.Error: Unresolved compilation problem:
The constructor ZipEntry(File) is undefined

at Zip.Zip.main(Zip.java:33)

Code:

---

package Zip;

import java.io.*;
import java.util.zip.*;

public class Zip {
  static final int BUFFER = 2048;
  public static void main (String argv[]) {
      try {
        BufferedInputStream origin = null;
        FileOutputStream dest = new FileOutputStream("C:\\Documents and Settings\\abc\\myzip.zip");       
        ZipOutputStream out = new ZipOutputStream(new BufferedOutputStream(dest));           
        //out.setMethod(ZipOutputStream.DEFLATED);
        byte data[] = new byte[BUFFER];
        //get the list of files from the given path.
        File folder = new File("C:\\Documents and Settings\\abc\\Local Settings\\Temp\\ABCD\\Data");
        File[] listOfFiles = folder.listFiles();

        for (int i = 0; i < listOfFiles.length; i++) {               
          FileInputStream fi = new FileInputStream(listOfFiles[i]);             
            origin = new BufferedInputStream(fi, BUFFER); 
            // Add ZIP entry to output stream.
            out.putNextEntry(new ZipEntry(listOfFiles[i]));      ------------------------------------------------->This line is pointed as error .... Any help is appreciated .
            int count;
            while((count = origin.read(data, 0,BUFFER)) != -1) {             
              out.write(data, 0, count);
            }
            origin.close();
        }//end of for loop
        out.close();
      } catch(Exception e) {
        e.printStackTrace();
      }
  }
}

---

Thank You In Advance

What constructors does ZipEntry have.
Have you looked at the API to see?

Sir

i did see the APIs for ZipEntry

Constructor Summary
ZipEntry(String name)
Creates a new zip entry with the specified name.
ZipEntry(ZipEntry e)
Creates a new zip entry with fields taken from the specified zip entry.


How do i change the code ....to add the constructor and make it run.

Pls help me solve this problem .

You're not providng it either a String or a ZipEntry are you, you're providing it a File.
SO you need to figure out what you can use in File that makes sense to supply to the constructor.

Not very sure about the logic here, but probably go ahead with adding the filename to the ZipEntry Constructor.
ZipEntry(listOfFiles[i].getName())