subclass calling superclass method

[stackptr89]

I am having trouble calling superclass method. Here is recent code

import java.util.*;
 public class Mercedes
 
{

  protected int [] ix = new int [50];
  protected int chamu;
  protected int icounter;

 //Class constructor

 public Mercedes ( int one, int two, int [] three)
  {

     icounter = one; 
     chamu = two;
     ix = three;
  }
  
   //method to take user input and load into array

 public void icards (int icounter, int chamu, int [] ix )
     {
 
    }

 //End of Method


}
 //End of Class


 
public class MercedesTest extends Mercedes
{
  //Subclass Constructor
  public MercedesTest ( int one, int two, int [] three) 
    {
      //calls superclass constructor
       super ( one, two, three ); 
    }
      //This line(10) throws error! Attempts to calls superclass method
     super.icards( int one, int two, int [] three);
 }

Here are the errors I get:

MercedesTest.java:10:illegal start of type
MercedesTest.java:10: ';' expected
MercedesTest.java:10: invalid method declaration; return type required

any suggestions greatly appreciated

[JosAH]

I've searched around but could not find anything. I get "illegal start of type" and "invalid method declaration" errors. Suggestions greatly appreciated

Count your curly brackets and see if they match up.

kind regards,

Jos

[stackptr89]

Yes they do.

[JosAH]

Yes they do.

No they don't.

kind regards,

Jos (<-- loves to have an argument ;-)

[stackptr89]

sorry I missed that last bracket when I copied/pasted

[Fubarable]

sorry I missed that last bracket when I copied/pasted

If you're still having the error, then please post the most recent code, nicely formatted, the full error message, and indicate in the code with a comment, which line is causing the error.

Luck!

[stackptr89]

my recent code is on there. tried to make it as easy as possible to read. thanks

[Fubarable]

my recent code is on there. tried to make it as easy as possible to read. thanks

The code you've posted has not yet corrected all curly brace problems and has not indicated by comment the line causing the error. I can wait.

[m00nchile]

Your problem is actually caused by the fact that the method call is in "no mans land". That method call should occur inside another method or perhaps a constructor. If you don't want to modify the behavior of the method (eg. does the same thing if called by subclass or superclass) you don't need to define the method again in your subclass:

public class Parent {
  public void foo() {
    System.out.println("bar");
  }
}

public class Child extends Parent {
  //other methods and all that jazz
}

public class Test {
  public static void main(String[] args) {
    Child c = new Child();
    c.foo(); //will print out bar
  }
}

[stackptr89]

JoshAh, Fubarable I thought I fixed it but thanks for looking.
m00nchile thanks!!! :D

[JosAH]

      //This line(10) throws error! Attempts to calls superclass method
     super.icards( int one, int two, int [] three);

When you call a method you don't mention the types of the arguments; those types are defined when the method was defined; you call it like this:

     super.icards(one, two, three);

When there is no method icards( ... ) defined in the current class the compiler will check whether or not it is defined in a superclass, so here you can delete the "super." prefix.

kind regards,

Jos