Split a String with split()--Help

[danilson]

Hi everyone,

I am taking an array from a webpage and I am putting all its html code in a string (k). Now I want to split that string so that I will only have the info in a table (each line in a seperate cell). I want to split it (using </tr> as delimiter) but keep the </tr> and not loose it. How can I do that?

String[] x = k.split("</tr>"); //This line looses the </tr>.
I would also appreciate any other suggestions.

[JosAH]

Hi everyone,

I am taking an array from a webpage and I am putting all its html code in a string (k). Now I want to split that string so that I will only have the info in a table (each line in a seperate cell). I want to split it (using </tr> as delimiter) but keep the </tr> and not loose it. How can I do that?

String[] x = k.split("</tr>"); //This line looses the </tr>.
I would also appreciate any other suggestions.

Glue it back on afterwards?

for (int i= 0; i < x.length; i++)
   x[i]+= "</tr>";

kind regards,

Jos

[danilson]

Well...thanks. Of course this works. But I think there is a way of using split without loosing the delimiter and I can't find and use it properly. It is something like
x.split("(?<=[!])") if the ! is the delimiter, but I can't adjust it into my case.

[JosAH]

Well...thanks. Of course this works. But I think there is a way of using split without loosing the delimiter and I can't find and use it properly. It is something like
x.split("(?<=[!])") if the ! is the delimiter, but I can't adjust it into my case.

Reluctant quantifiers don't do anything for the split( ... ) method; what you have in mind won't work, i.e. that method removes the delimiter String/regular expressions.

kind regards,

Jos

[eRaaaa]

Reluctant quantifiers don't do anything for the split( ... ) method

Mhm? That is not a reluctant quantifier or? Thats a special construct and is standing for:
"(?<=X) X, via zero-width positive lookbehind"

Pattern (Java Platform SE 6)

as an example

		String k = "<tr>hello</tr><tr>world</tr>";
		String[] x = k.split("(?<=</tr>)");
		System.out.println(Arrays.toString(x));

the output is : [<tr>hello</tr>, <tr>world</tr>] but if </tr> is not the end of the string, the balance after </tr> will find a place in your array too :)

can you give an example, how your string looks like and and how you want your array to be filled?

[danilson]

Mhm? That is not a reluctant quantifier or? Thats a special construct and is standing for:
"(?<=X) X, via zero-width positive lookbehind"

Pattern (Java Platform SE 6)

as an example

		String k = "<tr>hello</tr><tr>world</tr>";
		String[] x = k.split("(?<=</tr>)");
		System.out.println(Arrays.toString(x));

the output is : [<tr>hello</tr>, <tr>world</tr>] but if </tr> is not the end of the string, the balance after </tr> will find a place in your array too :)

can you give an example, how your string looks like and and how you want your array to be filled?

This was what I was looking for. I did something very stupid and it didn't work before. I used "" in a wrong way. Thanks a lot.

[danilson]

Oh, and by the way, </tr> is the end of my string so there is no problem. Thanks again

[JosAH]

Mhm? That is not a reluctant quantifier or? Thats a special construct and is standing for:
"(?<=X) X, via zero-width positive lookbehind"

Friday afternoon and I've learned something new; thanks for that.

kind regards,

Jos