Help explaining the difference.

[Romally]

Okay so I have two snippets of code, that to me should be doing the same thing, yet they act differently:

                System.out.println( "Please enter your course name:");
		String nameOfCourse = input.nextLine(); // Input prompt
		myGradeBook.setCourseName( nameOfCourse ); // Store name
		
		System.out.println( "Please enter your course name:");
		String nameOfCourse2 = input.nextLine(); // Input prompt
		myGradeBook2.setCourseName( nameOfCourse2 ); // Store name
		
		
		System.out.println( "Please enter your course name:");
		String nameOfCourse3 = input.nextLine(); // Input prompt
		myGradeBook3.setCourseName( nameOfCourse3 ); // Store name

and

                // Account 1
		
		System.out.println( "How much would you like to deposit? " );
		depositAmount = input.nextDouble();
		System.out.printf( "\nadding %.2f to account1 balance...\n\n",
				depositAmount);
		account1.credit( depositAmount );
		
		// Account 2
		
		System.out.println( "How much would you like to deposit? " );
		depositAmount = input.nextDouble();
		System.out.printf( "\nadding %.2f to account2 balance...\n\n",
				depositAmount);
		account2.credit( depositAmount );

Notice the variable in the parameters in account 1 and 2.credit are the same. Why won't this work when using strings? It forces me to use different names in the parameter in the gradebook.set areas.

If you need more info, just ask please.

[Fubarable]

Scanner#nextLine() swallows the end of line (EOL) token while Scanner#nextDouble() doesn't. If you grab the nextDouble token and also need to grab the EOL, then call input.nextLine() after calling input.nextDouble(). For example:

depositAmount = input.nextDouble();
input.nextLine(); // swallow the EOL token