Hey all, i'm putting this on a new post because I think the other one looks so big, no1 is looking at it... My objective is to make a table along the lines of this...

*******************************************
* a * b * c * area *
*******************************************
* 1 * 1 * 1 * *
* 1 * 2 * 2 * *
* 1 * 3 * 3 * *
* 1 * 4 * 4 * *

* 6 * 7 * 7 * *
***************************************


Q: Assuming a,b,c are integers and the circumference a+b+c is no larger than 20, create a program TriangleArea.java to enumerate all the combinations of edge lengths, and calculate the corresponding area of the triangle. Be aware that not all the combinations correspond to a valid triangle (the side lengths of a valid triangle must satisfy the triangle inequality). You should print "equivalent" triangles only once, e.g. a triangle with edge lengths (2, 3, 4) is "equivalent" to a triangle with edge lengths (4, 2, 3). The output from the program should be laid out as follows:


I think i have done everything I need now logic wise etc but I am unsure of how to enter code at the end that will actually produce something like the table above. It has been an epic day and I have now worked on this for 12 hours so any help getting me to the finish line would mean allot to me. Thanks xD

Atia

Java Code:
public class TriangleArea {

	public static void main( String[] args )
	{}
		
		int a;
		int b;
		int c;
		boolean isTriangle;{
		if ( (a+ b <= c) & (b + c <= a) & (a + c <= b) )
		{isTriangle = false;}
		else
		{isTriangle = true;}
		{
		   for (a= 1; a <= 20; a++) {
			   for (b= a; b <= 20; b++) {
			      for ( c= b; c <= 20; c++){
			      
			    	  if ((a < b+c) && (b < a+c) && (c < a+b)) break;
			    	  else continue;}}}}
			      }
			         public static double area(double a, double b, double c){
				    	   double s = Math.sqrt( (a + b + c) / 2 ) ;
				    	   double area = s * (s - a) * ( s - b ) * (s - c );
				    	   return  area;
				    	   System.out.println();
				    	   
				    	   
			      }
	}