Eliminating a line

[wizar]

I'm a little bit stuck with how to work with this piece of code:

  
for (int x = a; x <= p; x*=3) 
      {
        System.out.println(x);
      }
      for (y = b; y >= 1; y/=3)
      {
        if (y % 3 !=0)
        {
          System.out.println(y);
        }
        else 
        {
          System.out.print("");
        }
      }

All variables are integers.
For this code, y will not be outputted if it is a multiple of 3. However, I want x not to be outputted as well if y is a multiple of 3. I'm having trouble because I want x to be outputted before y.

I would also like to align the output with x in a column, and y in a column beside that. I don't think I can use "/t", so I was wondering how to use another for loop correctly (I can get the rows right, but I can't limit the columns correctly)? Or is there a better way of aligning the two outputs?

[tashimoto]

You might try nesting your for-loops and Only printing x after you have tested y ... maybe something like this:

for (int x=a; x<=p; x*=3) {
    for (y=b; y>1; y/=3) {
         if (y%3 != 0) {
             System.out.print(x + "\t");
             System.out.println(y);
          }
     }
}

BTW: I didn't check for correctness or syntax

[Zack]

In your code, Y is local to the second loop. It has no value while X is bring printed out.

Can you provide some sample output that you want to achieve?

[wizar]

Thanks for the idea tashimoto.

[venerik]

Hi Wizar,

I am not quite sure what problem you try to solve and how the output should look but you could consider to create a for loop with the initialisation, test and increment combined:

  for(x = a, y = b; x <= p && y >= 1; x *= 3, y /= 3) {
  }

Are you sure you want all variables to be ints? This means that after at most 2 iterations nothing will be displayed because after 2 iterations y % 3 will always result in 0.

Succes,
Erik

[wizar]

I didn't realize you could do that! Thanks! :)
And that code is all part of a larger program, no worries.