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 10242010, 08:49 PM #1Member
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Need help modifying code for hex conversion
Hi everyone. I'm new to Java and look forward to learning alot from here.
Currently I have a little problem with my code. I need to modify my existing java code which converts a base 10 value to base 10 and below. I need help modifying my code to allow for hex conversion also. My instructions are: Modify your program to handle base conversions up to base 16 (hexadecimal). Use if statements to substitute letters for numbers when the remainders are 10 or greater (for example, a remainder of 10 should be represented as “A”).
My code is the following:
Java Code:import java.util.*; // needed for Scanner public class Converter { public static void main (String [ ] args) { // Use this Scanner to read from the keyboard Scanner input = new Scanner(System.in); String answer = ""; System.out.print("Enter base 10 value to convert: "); int value = input.nextInt(); System.out.print("Enter base to translate into: "); int n = input.nextInt(); int quotient; int remainder; while (value>0) { quotient = value / n; remainder = value % n; value = quotient; answer = remainder + answer; } System.out.println("Answer: " +answer); } }
Thank you for your help.
 10242010, 09:16 PM #2Senior Member
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try:
int remainder; > char remainder;
remainder = value % n; > remainder = (char) ((value % n) > 9 ? ((value % n) % 10) + 65 : (value % n) + 48);
D:D
 10242010, 09:18 PM #3Member
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Thanks for the help, but the instructions say to use if statements.
 10242010, 09:21 PM #4
Inside the while loop you can just create 5 separate if statements:
Java Code:if(remainder = 10) if(remainder = 11) etc...
Then you just need a character to hold the hex value like eRaaaa said.Sincerely, Joshua Green
Please REP if I help :)
 10242010, 09:22 PM #5Member
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care to give an example as to how I would write this?
 10242010, 09:24 PM #6
Here's a little help to get you started, and actually I guess you won't need a char variable:
Java Code:if(remainder == 10) answer += 'A';
Sincerely, Joshua Green
Please REP if I help :)
 10242010, 09:25 PM #7Member
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Thanks. I'll see how I write this.
 10242010, 09:36 PM #8Member
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I can now get the letters to print normally, but they are in the wrong place. They dont seem to replace the remainder value and are added at the end instead (eg. converting 1000 to base 16 yields 3148E)
 10242010, 10:25 PM #9
 10242010, 10:30 PM #10Member
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I am using this as my code so far
Java Code:import java.util.*; // needed for Scanner public class Converter { public static void main (String [ ] args) { // Use this Scanner to read from the keyboard Scanner input = new Scanner(System.in); String answer = ""; System.out.print("Enter base 10 value to convert: "); int value = input.nextInt(); System.out.print("Enter base to translate into: "); int n = input.nextInt(); int quotient; int remainder; while (value>0) { quotient = value / n; remainder = value % n; value = quotient; if (remainder == 10) answer += 'A'; if (remainder == 11) answer += 'B'; if (remainder == 12) answer += 'C'; if (remainder == 13) answer += 'D'; if (remainder == 14) answer += 'E'; if (remainder == 15) answer += 'F'; answer = remainder + answer; } System.out.println("Answer: " +answer); } }

Hm, what if you swap your String concatenation:
Java Code:answer = "F" + answer;
 10242010, 10:42 PM #12Member
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well not really. We haven't gone over this in lecture yet.

It has nothing to do with your lecture and all to do with basic logic. If you're adding to the right of a String and dissatisfied that stuff is getting added to the right, simple logic states that you should add to the other side of the String. It basically means you should experiment with your code and try these things out.
Last edited by Fubarable; 10242010 at 11:28 PM.
 10252010, 06:50 AM #14Senior Member
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only a small note:
the ternary operator is a shorthand for an ifthenelse statement. (i think you have only two cases here, why should you check more than these two? (except as an exercise)
its the same if you would write
Java Code:int mod = value % n; if (mod > 9) { remainder = (char) (mod % 10 + 65); } else { remainder = (char) (mod + 48); }
AF are ASCII 6570
09 are 4857
 10252010, 07:59 AM #15Moderator
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