newbie guidance.

[eRaaaa]

why am i getting compile error with this so far?

:eek:
Try
System.out.println(jennifer.nextLine()); instead of System.out.println(jennifer.nextLine);

[Bgreen7887]

Obviously the default delimiter is the white spaces, is there a delimiter that would break the string into individual characters?

[m00nchile]

You can use the charAt() method for that, after you read in the entire String.

[Bgreen7887]

ok maybe better if i show you.. im trying to recieve a string and print each char on next line heres what i have so far , maybe you could write it up in puesucode and i'll try compile it

import java.util.Scanner;
public class ap  {
public static void main(String[]args)  { 

String n;
Scanner jennifer = new Scanner(System.in);
System.out.println("Please enter a String");
//jennifer.useDelimiter("");


while (jennifer.hasNext()) {
n = jennifer.next();
System.out.println(n);

        }

     }
}

[m00nchile]

Maybe it would be best if you write down the output you're trying to get, to avoid any confusion. What I'm getting from you, is that you want the user to input a string, and then print out every individual character in a new line. If that's the case, the pseudocode would be:

prompt user for input
store input in String variable
for every index from 0 to strings length - 1
  print out character at current index using charAt()
  new line
end loop

If that's what you're trying to achieve, you don't need to use a scanner more than once.

[Bgreen7887]

ok im reading string class api right now , getting past 3rd line of your code.

[Bgreen7887]

I cannot get that for loop...ughhh

[m00nchile]

Can you write a small snippet that has an array of 5 ints and use a for loop to print each array element in a separate line? Strings can be seen as arrays of chars, so the method of iterating through it is pretty much the same.

[Bgreen7887]

we haven't learned arrays yet only loops so im sure this is suppose to be done with loops.give me a sec i will try something else