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  1. 10-01-2010, 12:24 PM #1
    P5music
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    Default passing an entire file to a c++ function

    Hello
    I made a java application that is hosted in audio/midi sequencer Sonar through jVSTwrapper.
    This application create a .zip file and then pass to the host in getChunk() function. My implementation is:

    Java Code: 
    public int getChunk(byte[][] data, boolean isPreset)
{

int length = 0;
data = new byte[1][1];
String fileName="filename.zip";

File zipFile=new File(fileName);
FileInputStream fis=null;
        

	try {
             fis = new FileInputStream(zipFile);
        } catch (FileNotFoundException ex) {
            Logger.getLogger(myclass.getName()).log(Level.SEVERE, null, ex);
        }


length=(int)zipFile.length();data[0]=new byte[length];


        try {

            fis.read(data[0], 0, length);

        } catch (IOException ex) {
            Logger.getLogger(myclass.getName()).log(Level.SEVERE, null, ex);
        }


length = data[0].length;

        try {
            fis.close();
        } catch (IOException ex) {
            Logger.getLogger(myclass.getName()).log(Level.SEVERE, null, ex);
        }

return length;
}
    then, when requested, retrieves it from host and saves on disk with:

    Java Code: 
    public int setChunk(byte[] data, int byteSize, boolean isPreset)
{
    char[] arraychar=new char[byteSize];
    int i;
   
    FileOutputStream outStream=null;
    File outf=new File("filename.zip");

        try {
            outStream = new FileOutputStream(outf);
        } catch (FileNotFoundException ex) {
            Logger.getLogger(arpStylerVSTWrapper.class.getName()).log(Level.SEVERE, null, ex);
        }
        try {

            outStream.write(data,0,byteSize);

        } catch (IOException ex) {
            Logger.getLogger(arpStylerVSTWrapper.class.getName()).log(Level.SEVERE, null, ex);
        }
        try {
            outStream.close();
        } catch (IOException ex) {
            Logger.getLogger(arpStylerVSTWrapper.class.getName()).log(Level.SEVERE, null, ex);
        }


return 0;}
    The fact is that the restored file has the same size of the original one but I am not able to open it with winZip or winRar because I get an error like "damaged file or unknown format".
    Thanks in advance for your help.
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  2. 10-01-2010, 02:33 PM #2
    Norm's Avatar
    Norm
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    Default

    For more information, do you have a compare program that can compare the two files?
    You expect them to be byte for byte equal?
    Or write a simple java program that reads bytes from each and prints out when the bytes are different.
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  3. 10-01-2010, 03:39 PM #3
    P5music
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    Default

    the two file turn to be completely different, this is a sample:

    right file
    Java Code: 
    PK   A=            &   C:\myfolder\myfile.asy풿j0w!ON,K,;J7C1
Eˡ#%n$Q(%}t2&E1" [oz&~l~j_0Lm3}X3ukiVf4ٳ1|uK!*+EDPJ0$4%Rf@DJ(dJeB
*
/`܍vS*+
FјTѵ^?SXx%~lgCo5}dӛPKC %   ?  PK   A=               C:\myfolder\m_s.asyKw#׵&x	>  L A""P"E%յ$Kt-Kr.,[Rj)I夻G=̜T1?5tSuk*Uu	8c}$g+}ӒkXdq\atb߉?ş5O~vwŷ4oMV$xS~poZĶ4zoG_>X-
#V[G|u<z囒,yӈݛk_7E\Pg_I]_Xb.zu	;vH̘%~PkS4x<2ey	Vm#,ox$
K/LXVD9\r-MI9yyΣ߿ϜG$au|Lrhu_Uxʊ
    wrong file
    Java Code: 
     B4    Oa  B4    OP  B4    O*  B4    OT   B4    O  " B4    O   $ B4    O   & B4    O   ( B4    O   * B4    O   , B4    O   . B4    O4 0 B4    OPi 2 B4    O  4 B4    O   6 B4    O  8 B4    O   : B4    O  < B4    O   B4            с[E^ `                -    R	4!0 *	   HK   j   `    HK   j           HK   t   -    HK   Hq           HK   Hq   h    HK          HK              HK   ȅ   h.    HK   H       HK           HK              HK   H       HK      1    HK   H   .    HK   H   o    HK              HK      )    HK   H       HK   H   v    HK   H               Zk^   /0(0@0X0p00*000004         $0      \         <0         
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  4. 10-01-2010, 04:49 PM #4
    Norm's Avatar
    Norm
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    Default

    Why do you think that binary data will make it thru the reads and writes that you are doing and stay unchanged. Are there other programs that read/write the data besides the two methods you show?

    What does the "host" have to do with the transportation(reading/writing) of this data from the input zip file to the output file? Can the "host" have encoded/decoded the data?
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