Why do I get this output?

[Allspark]

public class testing
{
public static void main(String[] args)
	{
		final int a = 2, b = 3;
	
		System.out.println(a + "2");
		
		[COLOR="Red"]System.out.println(a + '2');[/COLOR]
		
		System.out.println("2" + a + b);
		
		System.out.println("2" + (a + b));
		
	
	System.exit(0);
	}
}

output is
22
52
223
25

How does the red highlighted code work? Thanks!

[Norm]

System.out.println(a + '2');

chars can be converted by the compiler to their ASCII value. If you lookup the ASCII codes table you will see that the int value of '2' is 50.

[DarrylBurke]

chars can be converted by the compiler to their ASCII value.

There's no conversion involved. The Java primitive char is an integral type.
Types, Values, and Variables

db

[JosAH]

There's no conversion involved. The Java primitive char is an integral type.
Types, Values, and Variables

Well, there is some conversion happening but it happens during compile time; b.t.w. literal chars are converted to their Unicode code point values, not their ASCII code values (which is totally moot because ASCII is a subcode of Unicode).

kind regards,

Jos