Using Regex

[ron87]

I am new to Java and i want to use regex class for pattern matching..

I am processing string like 003b , 002v
I want to check if any character is present(from a to z or A to Z) in the above string using regex.

Can some one help me?

[Zack]

Can you provide a set of valid/invalid values?

For example:

001a - good
001b - good
001f - bad
002e - good

..that kind of thing.

If you just want to check if an alphabetic character is in the string, you can use this kind of thing:

		String s = "001a"; // Can be whatever string you want here...
		Pattern p = Pattern.compile("[a-z]+");
		if (p.matcher(s).find())
			System.out.println("Found!");
		else
			System.out.println("Did not find!");

Full Java Regex tutorial: Lesson: Regular Expressions (The Java™ Tutorials > Essential Classes)
Wikipedia on Regex: Regular expression - Wikipedia, the free encyclopedia

[ron87]

it can be any string like 002d

I tried it like below

public static void main(String [] args) {
String s = "001d";
Pattern pattern = Pattern.compile("[a-zA-Z]");
Matcher matcher = pattern.matcher(s);
if(matcher.matches()){
System.out.println(s);
}
}

but above code never printed 's' coz if condition was always false.
So i was confused.

[Zack]

The .matches() attempts to match the pattern with the ENTIRE string. That means that only single characters will match your pattern.

However, if you use .find(), it will find it anywhere in the string.

Is that what you're looking for?

[ron87]

Yes mate.. i got it now..
thanks for ur help

Cheers,:)