Linking two classes together

[JonniBravo]

Hi,

I have created an opening Menu in my project using eclipse and got it to print some text when you select an option. I want to create a sub menu of the same type as the first when one of the menu options is selected, so I have copied the menu code into a new class.

The plan is to create four classes for the four options in the menu and switch to the relevant class clicked.

Problem is I don't know how I switch to the new menu. Below is a snippet of my code:

String[] names = new String[] { "Premiership", "Championship", "League One", "League Two"};
// Create an ArrayAdapter, that will actually make the Strings above
// appear in the ListView
this.setListAdapter(new ArrayAdapter<String>(this,
android.R.layout.simple_list_item_checked, names));
}

@Override
protected void onListItemClick(ListView l, View v, int position, long id) {
super.onListItemClick(l, v, position, id);
// Get the item that was clicked
Object o = this.getListAdapter().getItem(position);
String keyword = o.toString();
Toast.makeText(this, "You selected: " + keyword, Toast.LENGTH_LONG)
.show();


}
}

[Norm]

Can you make a small program that compile and executes and demonstrates the problem. Your snippets are pretty skinny.

[JosAH]

I want to create a sub menu of the same type as the first when one of the menu options is selected, so I have copied the menu code into a new class.

That begs for refactoring ...

kind regards,

Jos

[JonniBravo]

Here is the code for the first menu:

	
	import android.app.ListActivity;
	import android.os.Bundle;
	import android.view.View;
	import android.widget.ArrayAdapter;
	import android.widget.ListView;
	import android.widget.Toast;

	public class League2 extends ListActivity {
		public void simpleMessage(){}
		
		public void onCreate(Bundle icicle) {
			super.onCreate(icicle);
		
			String[] names = new String[] { "Pre", "Cham", "L2", "L1"};
		
			this.setListAdapter(new ArrayAdapter<String>(this,
					android.R.layout.simple_list_item_checked, names));
		}

		
		protected void onListItemClick(ListView l, View v, int position, long id) {
			super.onListItemClick(l, v, position, id);
			

			Object o = this.getListAdapter().getItem(position);
			String keyword = o.toString();
			Toast.makeText(this, "You selected: " + keyword, Toast.LENGTH_LONG)
					.show();

		}
	}

What I want to do rather than printing the option selected I want to go to a new menu or Class. How would I do this, sorry if I'm not making much sense.

The Second menu is the same code but I have renamed the options

[Norm]

That's a bit more code than the snippets but still isn't an executable program.

Just noticed: import android

That'll probably take a different SDK than most of us have.

[Zack]

Give this link a try instead, it's a dedicated Android Development Forum.
Android Development

[m00nchile]

What I'd reccomend is starting with an abstract Menu class, extending it to the submenus you want to create, and then making a MenuManager class that switches the displayed menu, something like this:

public class MenuManager {
  //constructors, code...
  public void respondToClick(Menu newMenu) { //next submenu
    //draw the new menu on screen
  }
}

Think of this as an MVC (Model View Controll) type of organisation, ModelManager is your View, the different Menu classes are the Model, and another class that executes the menu commands is the Control.