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 09092010, 07:54 AM #1Member
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Array[] get smallest/largest value
Hi,
How would you determine the smallest and largest value if you have the following:
These are double numbers and there can be many arrays, as many as the user inputs.
Java Code:Double array[] = new Double[10000]; array[i] = n;
Java Code:array[0] = 5 array[1] = 1 array[2] = 9 array[3] = 6
 09092010, 08:06 AM #2
Make a loop through, from i = 0 to i < length of array, to loop through every item of the array.
Keep a variable, declared at the start of the loop, which sets to the current number if it's higher/lower than its previous value. For example, here is some pseudocode:
Java Code:arr = { 1, 7, 36, 2, 9, 18 }; somevar = 1; for (i in (0, arr.length  1)) { if (arr[i] > somevar) { somevar = arr[i]; } } // Here, somevar is equal to the highest value of the array.
You can do the same for lowest value, using something like 9999999 instead of 1 as somevar's initial value (and checking < instead of >). Of course, this is just pseudocode, but you should have no problem translating it to Java.
Good luck!
 09092010, 08:30 AM #3Senior Member
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Arrays.sort() and take the first and last.
 09092010, 02:35 PM #4Member
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I've tried both of those methods, but I don't think I've translated them correctly.
Java Code:array[0] = 5 array[1] = 1 array[2] = 9 array[3] = 6 Double somevar = 1.0; for (int index = 0;index < array.length1; index++) { if (array[i] > somevar) { somevar = array[i]; System.out.println("This is somevar high = " +somevar); } }
 09092010, 02:50 PM #5Senior Member
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You've tried Arrays.sort()? And it didn't work? Sorry, but I don't believe that.
 09092010, 02:57 PM #6
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 09092010, 04:00 PM #7This returns an error
 09092010, 08:49 PM #8Member
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I know PHP which is kind of like a simplified JAVA. But it turns out that Double can't be ordered. It has to be an int.
What I ended up doing is comparing each value that was input to the previous value.
Java Code:if (i > 0) { int itest = i1; if (array[i] > array[itest]) { largest = array[i]; } }
Cheers

 09092010, 09:00 PM #10
I have to agree with Fubarable here. That's not true...
Not really sure why you did it this way. This only compares it to the preceding value. Let's say you have this array:
Java Code:{12, 15, 3, 5}
Example:
Java Code:int[] array = {12, 15, 3, 5}; int largest = 9999; for (int i = 0; i < array.length; i++) { if (i > 0) { int itest = i1; if (array[i] > array[itest]) { largest = array[i]; } } } System.out.println("Bobo's method: "+largest); largest = 9999; for (int i = 0; i < array.length; i++) { if (array[i] > largest) { largest = array[i]; } } System.out.println("Zack's method: "+largest);
Java Code:run: Bobo's method: 5 Zack's method: 15
Hopefully you see why your method does not work as you described. If not, let me know and I can explain further. Cheers!
 09092010, 11:42 PM #11Member
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Yea I know that my code does not accomplish the desired result. I got an A for it though.
What if you have
int[] array = {12.1, 15.9, 3.0, 5.0};
I don't understand how you would compare those values with Double.
 09102010, 12:09 AM #12
The code line you posted does not compile.
What error message do you get when you try to compile it?
 09102010, 12:14 AM #13Member
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Unresolved compilation problems:
Type mismatch: cannot convert from double to int
 09102010, 12:16 AM #14Senior Member
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