Java Syntax If statement

[Blasz]

I was wondering if there was a shorter way of typing,

if(a==this||a==that)

[wsaryada]

It short enough for me :) what's the real problem with that?

[Blasz]

my "this" and "that" are very long and i can't go over the 80 character width so it effectively adds unnecessary lines to my code.

I tried if(a==(this||that)) but it didnt work.

[wsaryada]

You can always refactor your very long "this" and "that" expression into methods which you can call from the if statement.

[Blasz]

Ok thanks for that. Now a totally different question.

How can i catch a ArithmeticException, i try

catch(ArithmeticException)

but it doesnt recognise ArithmeticException.

[Tolls]

What do you mean by "doesn't recognise".
When you get exceptions or compilation errors you really need to post the exact error you are getting.

[Blasz]

Sorry i figured it out, I wasnt using try {}, and also i didnt put an identifier after the arithmeticexception,

eg. ArithmeticException e

[Eranga]

But that's not really mean "dosen't recognize". If you have a look at your error message then you can find the most suitable word for that. Try to stick with them. :)

[Blasz]

Sorry about that, the proper error was "ArithmeticException cannot be resolved".

All good now though :)

[Eranga]

Not as it is. ;)