where the stuff goes?

Code:

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class Uppg2{
        public static void main(String[]args){
              Fnyrr[] obj = new Fnyrr[4];
              obj[0]=new Hocke(1);
              obj[1]=new Smatte();
              obj[2]=new Smatte();
              obj[3]=new Hocke(3);
              for (int x=0; x<obj.length; x++)
                  obj[x].skriv(4);
      }
}

---

Code:

---

class Fnyrr{
      public static String[]färg={"Rod","Bla","Gul","Vit","Gron"};
      public static int nummer=0;
      public String minFärg="Svart", djur="Bjorn";
   
      public Fnyrr(){
            minFärg=färg[nummer++];
      }

      public Fnyrr(int tal, String djur){
            minFärg=färg[tal];
            this.djur=djur;
      }

      public void skriv(int antal){[B][I]// what is "antal" here for first time for Hocke(1)[/I][/B]
            for (int x=nummer; x<antal; x++)
                  System.out.println(minFärg+" "+djur);
      }
}

---

Code:

---

class Hocke extends Fnyrr{
        public static String[] alla={"Katt","Hund","Gris","Elefant"};

        public Hocke(int tal){
              super(tal, alla[tal]); //[I][B] is it here goes 1 from Hocke(1)? to "tal " and to "all [tal]"[/B][/I]
        }
}

---

Code:

---

class Smatte extends Fnyrr{
        public String grej="Igelkott";

        public void skriv(int antal){
              System.out.println(grej);
              super.skriv(3);                  [B][I]//where 3 goes ?[/I][/B]
        }
}

---

[/I]Answer:[/I]
Bla Hund two times ?? why
Bla Hund
Igelkott
Rod Bjorn
Igelkott
Bla Bjorn
Vit Elefant
Vit Elefant

Quote:

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public void skriv(int antal){// what is "antal" here for first time for Hocke(1)

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You need to read about how methods receive arguments. antal is an int argument to the skriv method.

Quote:

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super(tal, alla[tal]); // is it here goes 1 from Hocke(1)? to "tal " and to "all [tal]"

---

What is your question?
This code passes two arguments to the constructor of the super class.

Quote:

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super.skriv(3); //where 3 goes ?

---

This code passes one arg to the constructor of the super class.

Quote:

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two times ?? why

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Because of the logic of the program. That is what the program is coded to do.

Try debugging the code by adding more println()s to show how variables are set and their values changed as the program executes.

Take a piece of paper and write down the on each line, just running the code on your mind. Or else as Norm suggest you, debug the code and check values in each steps.

sorry guys but to early for me to get it what do you talking about...anyways ..I did debugging, well at least I did try to do that.
Still can not get it why program writes 2 times Bla Hund but not 4 times? 4 times because is 4 places in array so the "antal" is 4.
confusing what goes first and where.
i know the passing from constructor to super class but in what order in this case?
is it any other way to write debugging than by for example : System.out.println(x);

Another thing that I want to highlight here. Please use code tags when you are posting again. Unformated codes are really hard to read.

Did you write this code in an IDE or on simple editor such as notepad and so on? If you are working on an IDE then add few breakpoints and debug the code, it's most suitable way.

If not take a piece of paper and write down the output in each line, just by running your code from your mind, and check the logic.

Quote:

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any other way to write debugging than by for example : System.out.println(x);

---

Yes. What you show is not a good way to do it. You need to add an id for the output:
System.out.println("x=" + x);

hmm... weired but is not working even with your ,NORM,nicer version of code. I could not see x. :(

Well....
in this part at the very beginning
public void skriv(int antal){
for (int x=nummer; x<antal; x++)
System.out.println(minFärg+" "+djur);
}

x is 0 taken from "nummer=0; " in super class, right?
and
"antal "is 4 as 4 places in array,
so how come For-loop is stopped after two times? with result Bla Hund, Bla Hund?

Change this:
public void skriv(int antal){
for (int x=nummer; x<antal; x++)

to this:

public void skriv(int antal){
System.out.println("antal=" + antal + ", nummer=" + nummer); // show values
for (int x=nummer; x<antal; x++)

thanks, Norm, it's good to see this x=nummer; finaly....so how this x increases from 0 to 2?
I do not see any nummer++ ..... where this nummer=0; which I think is x in For-loop changes to 2? Where I understand x is starting with this value 2 and go through For-loop. Seems, all the times x is starting with value 2.

Did you add the following to your code:
System.out.println("antal=" + antal + ", nummer=" + nummer); // show values
What was the value of nummer that printed?

Quote:

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all the times x is starting with value 2

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x starts with the value in nummer? Which you printed out on the println() above.

ye , nummer is 2.

Does that answer your question?

Partly, yes but I want to know how did happen that x is 2.... where is it in this code ? what I am missing?
this is so confusing...where this 2 came from?

p.s.

Thanks for all you answers...:)

This will change the value of nummer:
minFärg=färg[nummer++];

This will set x to the value of nummer:
x=nummer

Add some more println()s to show the value of nummer.

hi...well is it not that "nummer " has value 0 at the beginnig and let say ok...changes by "minFärg=färg[nummer++]; " ,but is it not that volue of "nummer" is 1? why is it 2 than? How it happens that" nummer "has value 2 when become x, in For-loop?
How to think here???

Do I ever understand java logic?...Gosh..ufff ;)

All I can recommend is: Add some more println()s to show the value of nummer.