Converting double to char array?

[Blasz]

I have to detect whether a double is a fraction or not.

So, coming from a C background, I thought I should convert the double to an array of chars and check to see if theres any non-zero numbers to the right of the decimal place.

Is this the right way to go about it? If it is, how would i do it?

I don't think I'm allowed to import any packages.

[JosAH]

I have to detect whether a double is a fraction or not.

So, coming from a C background, I thought I should convert the double to an array of chars and check to see if theres any non-zero numbers to the right of the decimal place.

Is this the right way to go about it? If it is, how would i do it?

I don't think I'm allowed to import any packages.

Check out the (static) methods in the Math class; if x == Math.ceil(x) there is no fractional part in x; equivalent: if x == Math.floor(x) there is also no fractional part in x.

kind regards,

Jos

[Blasz]

Thanks man, just a few more questions (I only started learning Java today).

Where do I check out these methods in math class (or any class).

My JRE System library is jdk1.6.0_12, does that affect how many classes I can use?

Is the Math class a basic in-built class that is attached to every java library?

Where can I find all the different classes for my JRE System library (assuming that is where all the classes come from?)

Yes, I'm very noob at java.

EDIT: Also, with your example wouldn't it be x + 1 == Math.ceil(x) or x = Math.ceil(x+1)?

[Fubarable]

You want to check out the Java API, the latest edition (as of this writing) of which can be found here: Java 1.6 API

[JosAH]

Thanks man, just a few more questions (I only started learning Java today).

Where do I check out these methods in math class (or any class).

My JRE System library is jdk1.6.0_12, does that affect how many classes I can use?

Is the Math class a basic in-built class that is attached to every java library?

Where can I find all the different classes for my JRE System library (assuming that is where all the classes come from?)

Yes, I'm very noob at java.

EDIT: Also, with your example wouldn't it be x + 1 == Math.ceil(x) or x = Math.ceil(x+1)?

You can bookmark or download the stuff from this link. Java 1.6 is the latest version so you are up to date. Never program anything without checking the API documenation. The Math class is in the java.lang package and that package is included implicitly so you don't have to import anything. For starters read the description of the Math.ceil( ... ) method and you'll see that if x == Math.ceil(x) there is no fractional part in x.

kind regards,

Jos

[Blasz]

True, thankyou so much.

[Blasz]

Ok turns out I probably will need to convert a double to a char array as I need to know how many digits there are to the right of the decimal place.

How would I do this?

[JosAH]

Ok turns out I probably will need to convert a double to a char array as I need to know how many digits there are to the right of the decimal place.

How would I do this?

Think of it: how many decimals are there in the fraction part of 3.000000? Maybe you should check one of the Formatter classes such as the DecimalFormat class ...

kind regards,

Jos

[Blasz]

Hmm, well this is for a different part of the program. I will need to know how many zero's are right of the decimal if they are all entered but I'm guessing double would just cut them off and keep the value equal to 3.0?

I had a look at DecimalFormat but it looks very daunting, could you explain a little bit of what it does / how I could use it?

[JosAH]

Hmm, well this is for a different part of the program. I will need to know how many zero's are right of the decimal if they are all entered but I'm guessing double would just cut them off and keep the value equal to 3.0?

I had a look at DecimalFormat but it looks very daunting, could you explain a little bit of what it does / how I could use it?

Well, that class returns a String given a 'format specifier' (also a String) telling it how to format a number and a number to format. Try it and when/if you're stuck ask questions about it here.

kind regards,

Jos