why this doesn't work?

[hitesh_public]

Hello friends, I am very new to programming. I want to know why this code doesn't work.

void linkedListMenu() 
  throws IOException 
  {
    int c;
    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    do {
      System.out.println("Choose one of the following options:");
      System.out.println("\t1.Create the Linked List");
      c = br.read();
      System.out.println("how" + br.read() + "are you");
    } while(c != 1);
  }

But when i use this form this works:

void linkedListMenu() 
  throws IOException 
  {
    char c;
    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    do {
      System.out.println("Choose one of the following options:");
      System.out.println("\t1.Create the Linked List");
      c = (char) br.read();
      System.out.println("how" + br.read() + "are you");
    } while(c != '1');
  }
}

[masijade]

Please describe "doesn't work", in detail.

[Fubarable]

Moderator edit: italics removed, code tags added for readability. To learn how to do this yourself, please check out the links in my signature.

Much luck!

[Zack]

You should really specify exactly what isn't working.

However, I believe I see the problem. Read up on BufferedReader.read() and you should be able to figure it out too. BufferedReader (Java 2 Platform SE v1.4.2)

[Gahstanz]

When after prompting for the user value and storing it into a variable, e.g
System.out.println("\t1.Create the Linked List");
c = br.read();

This is trying to force a string value into an int variable.
To implicitly cast the value into the variable you would write:
c = Integer.parseInt(br.read());

or explicit by

c = (int) br.read();

[masijade]

When after prompting for the user value and storing it into a variable, e.g
System.out.println("\t1.Create the Linked List");
c = br.read();

This is trying to force a string value into an int variable.
To implicitly cast the value into the variable you would write:
c = Integer.parseInt(br.read());

or explicit by

c = (int) br.read();

No. The read method returns an int. (besides "casting" a String to an int, like your second example, wouldn't work any way)

I have a feeling that the OP is complaining that the first time it prints a number rather than a character, and the second time it prints a character. This is perfectly understandable, since he is reading an int the first time a char (character) the second time, but until the OP describes exactly what his "problem" is this conjecturing is useless and probably counter-productive, when not outright wrong, like the previous post.