Finding a word in a sentence?

[blackrabbit]

Hi, I'm very new to java and am a bit lost really.

I'm working with a String called 'sentence', which equals "the quick brown fox jumped over the lazy dog."

How can I query this, asking if the sentence includes the word "fox", printing the result as "Yes", or "No if "fox isn't part of the sentence? Would this have to be done in an array, or am I way off the mark?

Thanks in advance!

[Zack]

You could do it in an array; I believe Java supports tokenizing a String (splitting it up into "tokens" based on a specific character as a separator). You could also do it by looping through each character in the string.

I'd suggest looking at these:
StringTokenizer (Java 2 Platform SE v1.4.2)
Parsing Strings with split
loop through a string in java - Java answers

Good luck!

[bopeep123]

You can use the indexOf method of the String.

String string = "the quick brown fox jumped over the lazy dog.";
Boolean b = string.indexOf("fox") > 0;

This is case-sensitive. If you want it to ignore the case just use regex.

Hope this helps.

[Zack]

That would also find "abcfoxdef" in the sentence though. He'd have to then check if the string started with "fox ", if " fox " was in the sentence, or if it ended with " fox".

[Norm]

OP needs to consider what the definition of a word is. What are its delimiters?
white spaces, punctuation, or ()s or ???
Could have a method the took a char and returned true if the char was a valid word delimiter. Then with indexOf() finding a substring, testing for valid delimiters.

[j2me64]

		String sentence = "the quick brown fox jumped over the lazy dog.";
		System.out.println(sentence.contains("fox") ? "yes" : "no");

[Norm]

But does the contains() method test if the found substring is a word?
I think it only finds substrings.
The requirements: if the sentence includes the word "fox"