To read tags from file

[Cylab]

From file read the data : <a><c><d>e</d></d></a>

Output: ERROR: Mismatching tags on line 1: <c> and </d>!

Code is:

import java.io.BufferedReader;
import java.io.FileReader;
import java.util.*;

class Test6{

public static void main(String[] args)throws Exception{

Stack<Character> stack = new Stack<Character>();

BufferedReader br = new BufferedReader(new FileReader("c://test//assignment//input7.txt"));
String s;
int counter=0;
while((s=br.readLine())!=null){
char temp[] = s.toCharArray();
for(int i=0;i<temp.length;i++){
if(Character.isLetter(temp[i])){
...................
......................
.................
}}
}
br.close();
}
}

Could anyone kindly provide any solution for it?? Anything at all.
Or algorithm for it. I think I tried my best, unfortunately still could not do it:(
Pleaseeeeeeeeeeeeeeeeeeeeee!!!!!!!!

[Norm]

Sounds like you need to keep track of the state of the scan (perhaps by using booleans).
When you find a begin marker, set a flag to remember it.
Then if you find an end marker without having read a begin marker, that would be an error.
When you find the end marker, turn off the begin marker.
You'd probably need a stack to keep the state of the scan organized. The top of the stack would be the current begin marker. As the end was found, pop off the begin.

[JosAH]

Is this thread a sequel to this one?

kind regards,

Jos

[Eranga]

Seems discussing the same in two different threads.

[JosAH]

Seems discussing the same in two different threads.

Yep and the OP should've warned the potential repliers that some silly requirement doesn't allow him/her to use a simple xml parser (e.g. a SAXParser).

kind regards,

Jos

[Eranga]

I've remember that same user ask another related question to this. Have to check in my subscriptions.

[Cylab]

Yeah, I keep asking same kind of question since no right solution has been found yet.
Can anyone give a piece of code illustrate it. No need to have perfect answer, just need sth to push me to explore further. Thanks

[Eranga]

Yeah, I keep asking same kind of question since no right solution has been found yet.
Can anyone give a piece of code illustrate it. No need to have perfect answer, just need sth to push me to explore further. Thanks

So that it's not the best way to work around. There is no chance at all to have more answers by posting the same multiple times.