A clever way of doing this ... (avoiding a LOT of if-else statements)

[doejohn]

Hi, currently my code looks like this:

// Adjust x aim point
if(xWind < 0.50) {
	offsetX = 1;
} else if(xWind < 0.70) {
	offsetX = 1;
} else if(xWind < 0.80) {
	offsetX = 2;
} else if(xWind < 1.00) {
	offsetX = 5;
} else {
	offsetX = 7;
}
// Adjust y aim point
if(yWind < 0.50) {
	offsetY = 14;
} else if(yWind < 0.70) {
	offsetY = 16;
} else if(yWind < 0.80) {
	offsetY = 17;
} else if(yWind < 1.00) {
	offsetY = 18;
} else {
	offsetY = 19;
}

However, offsetX and offsetY should both depend on both yWind and xWind. So I need to combine the two, so that I can adjust both the X and Y offset for every combination of xWind and yWind, as such:

if(xWind < 0.50) {
	if(yWind < 0.50) {
		offsetX = 1;
		offsetY = 14;
	} else if(yWind < 0.70) {
		offsetX = 1;
		offsetY = 16;
	} else if(yWind < 0.80) {
		offsetX = 1;
		offsetY = 17;
	} else if(yWind < 1.00) {
		offsetX = 2;
		offsetY = 18;
	} else {
		offsetX = 2;
		offsetY = 19;
	}
} else if(xWind < 0.70) {
	if(yWind < 0.50) {
		offsetX = 1;
		offsetY = 14;
	} else if(yWind < 0.70) {
		offsetX = 2;
		offsetY = 17;
	} 
	// and so on...

But that results in 100s of if-else-statements. Is there a better way to do this? I need to be able to manually adjust the offsets for any range of xWind and yWind easily in my code.

[Fubarable]

The best way is to use a mathematical formula for calcuating x and y offsets based on the input. How that's done, I have no idea based on what you've told us. Perhaps you can tell us how these numbers are calculated?

[doejohn]

Ok thanks. I think the formula is hard to figure out manually, so I guess I'll have to collect as much data as possible so I can use a curve fitting tool to find polynomials that match the data (non-linear regression I guess).

[JosAH]

You can do without that long sequence of nested if-else statements but you have to supply the actual data in a couple of matrixes (or, as Fubarable suggested: find a functional depenceny fx(x, y) and fy(x, y) where both fx and fy are the wanted offsets).

Else a few data matrixes and a bit of code are a solution:

double winds[][] = // you have to supply the data here.
double[] windx[] = // you have to supply the data here.
int offsetsX[][] = // again, you supply the data here.
int offsetsY[][] = // again, you supply the data here.

for (int x= 0; x < windx.length; x++)
   if (windx[x] >= actualX)
      for (int y= 0; y < winds[x].length; y++)
         if (winds[x][y] >= actualY)
            // found a value for actualX and actualY: offsetsX[x][y] and offsetsY[x][y] are the answer ...

kind regards,

Jos