How do i convert a int to a binary with bitwise operators only?

[diskhub]

How do i convert a int to a binary with bitwise operators only?

And the output must have 32bits place

[Eranga]

What you exactly means by bitwise operator? What's your exact requirement also, because to convert the int into binary string you have several other approaches as well.

[diskhub]

i was told to use only bitwise operation
such as & | >> >>> << ~
to convert int to binary.

there cannot be multiplication n division used in the algorithm.

any clue?

[JosAH]

How do i convert a int to a binary with bitwise operators only?

And the output must have 32bits place

pst, don't tell them I told you but most (if not all) digital computers already store integers in binary format. No need to fiddle with them any further.

kind regards,

Jos

[diskhub]

ok, thks for informing
but that doesn't solve my problem

pls advise me how to print it in binary... 10101010111
such that i have to use bitwise operators only.

[JosAH]

ok, thks for informing
but that doesn't solve my problem

pls advise me how to print it in binary... 10101010111
such that i have to use bitwise operators only.

There are a couple of (static) methods in the Integer class that can help you.

kind regards,

Jos

[Norm]

Are you asking how to get a String representation of the binary value of an int?

To do that you need to look at each bit position of an int and test if its a 0 or a 1.
Use the AND operator for that.
Remember: 1 AND 1 = 1 1 AND 0 = 0

To look at all 32 bit positions, use the shift operator to move to the next position.

[Eranga]

No need to fiddle with them any further.

That's why I'm worried too Jos. Trying to somethings which already implemented, and which is easily could be solve in a messy way.

[Eranga]

ok, thks for informing
but that doesn't solve my problem

pls advise me how to print it in binary... 10101010111
such that i have to use bitwise operators only.

Yeah look around toBinaryString(int val) on the API for Integer class.

But still I'm confusing that why you really do that.

[Norm]

It sounded to me like a student's assignment to learn how to use bitwise operators. As an assembler programmer, I think it's good to know what's under the covers.

[Eranga]

It sounded to me like a student's assignment to learn how to use bitwise operators. As an assembler programmer, I think it's good to know what's under the covers.

Of course it could be. But my concern is that someone guide him in a very messy way.

[diskhub]

so no guide?
i thought of one... but might not be a prof way...

that's why i wanted to see what u expert can do... nevermind, i guess u guys are also not used to this tricky question. :D

[Eranga]

No lol. Everyone here in the forum wants to help, including me. But the way you got the question is bit a work. That's what we want you to pointed.

[Eranga]

Here comes the messy part there, from the API

private static String toUnsignedString(int i, int shift) {
	char[] buf = new char[32];
	int charPos = 32;
	int radix = 1 << shift;
	int mask = radix - 1;
	do {
	    buf[--charPos] = digits[i & mask];
	    i >>>= shift;
	} while (i != 0);

	return new String(buf, charPos, (32 - charPos));
    }

Can you understand that code segment?

[diskhub]

i am thinking of doing this... not sure whether this is good?

for every binary place of a NUM


if (NUM-(NUM>>1<<1)==1)
print "1"
else
print "0"

NUM= NUM>>1

LOOP

but i want to hear from you guys what plan u have?

[diskhub]

can u explain the following line of ur code:

int radix = 1 << shift; //what's the shift in this case? what to put for the arg Shift?

digits[i & mask]; // what abt this?

[Eranga]

can u explain the following line of ur code:

int radix = 1 << shift; //what's the shift in this case? what to put for the arg Shift?

digits[i & mask]; // what abt this?

shift = 1, think about it.

As I said earlier this is what Integer class does.

[Eranga]

for every binary place of a NUM

Can you please tell me that how you get the binary place in a number (I hope NUM means an integer value)

[diskhub]

interesting... i will explore it.
thanks for ur advice.

how's my method, any chance?

[Eranga]

interesting... i will explore it.
thanks for ur advice.

how's my method, any chance?

I've a question for you, in my last post.