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 05232010, 06:41 AM #1Member
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 05232010, 03:36 PM #2
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What you exactly means by bitwise operator? What's your exact requirement also, because to convert the int into binary string you have several other approaches as well.
 05232010, 03:39 PM #3Member
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i was told to use only bitwise operation
such as &  >> >>> << ~
to convert int to binary.
there cannot be multiplication n division used in the algorithm.
any clue?
 05232010, 05:09 PM #4
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 05232010, 05:13 PM #5Member
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ok, thks for informing
but that doesn't solve my problem
pls advise me how to print it in binary... 10101010111
such that i have to use bitwise operators only.
 05232010, 05:18 PM #6
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 05232010, 05:22 PM #7
Are you asking how to get a String representation of the binary value of an int?
To do that you need to look at each bit position of an int and test if its a 0 or a 1.
Use the AND operator for that.
Remember: 1 AND 1 = 1 1 AND 0 = 0
To look at all 32 bit positions, use the shift operator to move to the next position.
 05232010, 06:24 PM #8
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 05232010, 06:30 PM #9
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 05232010, 06:34 PM #10
It sounded to me like a student's assignment to learn how to use bitwise operators. As an assembler programmer, I think it's good to know what's under the covers.
 05232010, 06:43 PM #11
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 05242010, 01:45 AM #12Member
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so no guide?
i thought of one... but might not be a prof way...
that's why i wanted to see what u expert can do... nevermind, i guess u guys are also not used to this tricky question. :D
 05242010, 02:52 AM #13
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No lol. Everyone here in the forum wants to help, including me. But the way you got the question is bit a work. That's what we want you to pointed.
 05242010, 02:59 AM #14
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Here comes the messy part there, from the API
Java Code:private static String toUnsignedString(int i, int shift) { char[] buf = new char[32]; int charPos = 32; int radix = 1 << shift; int mask = radix  1; do { buf[charPos] = digits[i & mask]; i >>>= shift; } while (i != 0); return new String(buf, charPos, (32  charPos)); }
 05242010, 03:00 AM #15Member
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i am thinking of doing this... not sure whether this is good?
for every binary place of a NUM
if (NUM(NUM>>1<<1)==1)
print "1"
else
print "0"
NUM= NUM>>1
LOOP
but i want to hear from you guys what plan u have?
 05242010, 03:05 AM #16Member
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can u explain the following line of ur code:
int radix = 1 << shift; //what's the shift in this case? what to put for the arg Shift?
digits[i & mask]; // what abt this?
 05242010, 03:11 AM #17
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 05242010, 03:13 AM #18
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 05242010, 03:13 AM #19Member
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interesting... i will explore it.
thanks for ur advice.
how's my method, any chance?
 05242010, 03:15 AM #20
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