What's wrong with my (simple) code

[kracer]

import java.net.InetAddress;
public class Test2 {
	public static void main (String[] args) {
		InetAddress localaddr = InetAddress.getLocalHost();
		System.out.println ("Local IP Address : " + localaddr);
		System.out.println ("Local hostname   : " + localaddr.getHostName());
	}
}

I have this message when it si compiled

Exception in thread "main" java.lang.Error: Unresolved compilation problem: 

	at first.Test2.main(Test.java:13)

[kracer]

The line 13 is actually the line"public static void main (String[] args) {".
I didn't paste the whole code.

Thanks

[Fubarable]

I don't see you handling an exception:

import java.net.InetAddress;
import java.net.UnknownHostException;

public class Test2 {
  public static void main(String[] args) throws UnknownHostException {
    InetAddress localaddr = InetAddress.getLocalHost();
    System.out.println("Local IP Address : " + localaddr);
    System.out.println("Local hostname   : " + localaddr.getHostName());
  }
}

What happens if you do this?

[Fubarable]

I didn't paste the whole code.

Ah, since you don't know the cause of the error, it may be in your best interest to do a little debugging to isolate it. Try to find the smallest bit of compilable code that demonstrates this error and post it.

[JosAH]

What surprises me is that the compiler generated a class file despite the fact that a (checked) UnknownHostException wasn't trapped or declared to be thrown. I bet it at least warned about that fact (and should've aborted the entire compilation task without generating a .class file).

kind regards,

Jos

[Fubarable]

What surprises me is that the compiler generated a class file despite the fact that a (checked) UnknownHostException wasn't trapped or declared to be thrown. I bet it at least warned about that fact (and should've aborted the entire compilation task without generating a .class file).

Who knows what happened with this code, since the snippet provided was not complete and self-contained. Perhaps the exception was handled in the real code, perhaps not. Hence my request for small compilable code.

[JosAH]

Who knows what happened with this code, since the snippet provided was not complete and self-contained. Perhaps the exception was handled in the real code, perhaps not. Hence my request for small compilable code.

True, but still, one way or the other some .class file was generated and the jvm had to catch the exception (a compilation problem, caught during runtime). The OP sure did some strange things (unknowingly) ...

kind regards,

Jos

[kracer]

Here is the whole code.
[CODE]
package myTestingPackage;

import java.net.InetAddress;

public class Test2 {
public static void main (String[] args) {
InetAddress localaddr = InetAddress.getLocalHost();
System.out.println ("Local IP Address : " + localaddr);
System.out.println ("Local hostname : " + localaddr.getHostName());
}
}
[\CODE]
And here uis the error message. It has changed but I don't know why!

Exception in thread "main" java.lang.Error: Unresolved compilation problem: 
	Unhandled exception type UnknownHostException

	at myTestingPackage.Test2.main(Test2.java:7)

[JosAH]

And here uis the error message. It has changed but I don't know why!

Exception in thread "main" java.lang.Error: Unresolved compilation problem: 
	Unhandled exception type UnknownHostException

	at myTestingPackage.Test2.main(Test2.java:7)

Read the API documentation for the getLocalHost() method: it can throw the checked UnknownHostException. You either have to catch it or decare your main( ... ) method to throw it as well.

kind regards,

Jos

[kracer]

I don't see you handling an exception:

import java.net.InetAddress;
import java.net.UnknownHostException;

public class Test2 {
  public static void main(String[] args) throws UnknownHostException {
    InetAddress localaddr = InetAddress.getLocalHost();
    System.out.println("Local IP Address : " + localaddr);
    System.out.println("Local hostname   : " + localaddr.getHostName());
  }
}

What happens if you do this?

It works with your idea.
But I don't know why it does not work without the "throws UnknownHostException".
This may be a simple question. I am new to JAVA.

Thank you.

[JosAH]

It works with your idea.
But I don't know why it does not work without the "throws UnknownHostException".
This may be a simple question. I am new to JAVA.

Thank you.

Checked exceptions have to be handled by your code; either by declaring that your code lets it pass "throws ACheckedException" or by actually catching the exception and handling it. The compiler checks this and refuses to compile any code that doesn't handle such exceptions. It's a safety net.

kind regards,

Jos

[kracer]

Read the API documentation for the getLocalHost() method: it can throw the checked UnknownHostException. You either have to catch it or decare your main( ... ) method to throw it as well.

kind regards,

Jos

Thank you Jos.
So does this metohd throw always an UnkownHostException? Even if the IP address for the host could be found?

[kracer]

Checked exceptions have to be handled by your code; either by declaring that your code lets it pass "throws ACheckedException" or by actually catching the exception and handling it. The compiler checks this and refuses to compile any code that doesn't handle such exceptions. It's a safety net.

kind regards,

Jos

OK, it actually answers my latest question.

Thanks

[JosAH]

Thank you Jos.
So does this metohd throw always an UnkownHostException? Even if the IP address for the host could be found?

If a method states that it can throw an Exception it isn't obliged to always throw that Exception. It only throws it in exceptional circumstances. This method only throws that Exception if it can't find a local host and your code is supposed to handle that Exception when/if it is thrown because it is a 'checked' Exception. Your compiler checks it (as you already have noticed).

kind regards,

Jos