Help with my code to find MinOfAll numbers

[May.ver.rick]

I am new to Programming world and so to Java,

I tried my hands on writing the following code to find minimum of all the numbers entered via command prompt,
but I am getting the error

Exception in thread "main" java.lang.ArrayIndexOutOfBound Exception :5 at MinOfAll.main

Kindly tell me where am I going wrong?

public class MinOfAll{  
  
public static void main(String[] args){  
  
int result = Integer.parseInt(args[0]);  
for (int i =0 ; i< args.length; i++)  
{  
    int current=Integer.parseInt(args[i+1]);  
 if (current < result){  
     result = current;  
 }  
         
}  
System.out.println("Min of all is : " + result);  
  
  
}  
}  
  
[color=red]I/P at console : java MinOfAll 2 3 4 5 6[/color]

[Eranga]

Why did you do that?

int current=Integer.parseInt(args[i+1]);

should be,

int current=Integer.parseInt(args[i]);

Because arrays in Java are zero based indexing.

[May.ver.rick]

I did that to start the comparison with next element in the array.

Even tough I edit it to,

int current=Integer.parseInt(args[i]);

the output error still persists.

[Eranga]

How did you run your code? Did you pass relevant parameters?

[May.ver.rick]

This is what I do on console

java MinOfAll 2 3 4 5 6

[Eranga]

So that's the error. Can you show your correct code. I don't think that you fix the correct place.

[May.ver.rick]

public class MinOfAll{

public static void main(String[] args){

int result = Integer.parseInt(args[0]);
for (int i =0 ; i< args.length; i++)
{
	int current=Integer.parseInt(args[i]);
 if (current <= result){
	 result = current;
 }
	   
}
System.out.println("Min of all is : " + result);


}
}

[Eranga]

Right, so it' working. There cannot be any error at all. You say that you get the same error? It cannot happen.

[May.ver.rick]

My bad I had kept the same code at 2 places ad was running the unpdated one.

Thanks again!!

[Eranga]

You are welcome. :)

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