Exception in thread "main" java.lang.NumberFormatException: Value out of range. Value

[jav2000x]

Hi All,

I get this error while I am using parseByte() in my code and it is driving me mad

Exception in thread "main" java.lang.NumberFormatException: Value out of range. Value:"495051" Radix:10

My code is as shown below ...
I am trying to program DICOM's implementation of RLE using Bytes on image files. I tried it using String and works fine but performance is really bad. I am not very comfirtable of using bytes and encouterning many problems.

I am getting the error on this line

rtn_val[array_count]=Byte.parseByte(temp);

Thanks


==

public byte[] encodeBytes(byte[] inpByte){
            
            int length=inpByte.length;
            System.out.println("length "+length);
             for (int i=0;i<inpByte.length;i++){
                System.out.println(inpByte[i]);    
             }
             
            //byte[] temp = new byte[length-1];
            boolean replicate=false;
            int d_count=0;
            int count=0;
            byte[] rtn_val=new byte[length-1];
            int array_count=0;
            
            String temp="";
                    
            for (count=0;count<length;count++){
                System.out.println("in for loop" + inpByte[count]); 
                d_count=1;                            
                while(replicate==true && count+1 < length && inpByte[count] == inpByte[count+1]){                    
                    d_count++;     
                    count++;
                    System.out.println("loop1 "+inpByte[count]);
                }    
                while(replicate ==false && count+1<length && inpByte[count]!=inpByte[count+1]){                    
                    /*
                    int x=0;
                    if(temp==null){
                        System.out.println("in here");
                        x=0;
                    }else{
                        x=temp.length-1;                        
                    }
                    System.out.println("COUNT " + count +" and inpByte[] " + inpByte[count]);
                    temp[x]=inpByte[count];
                    */                                      
                    temp+=inpByte[count]; //Using String instead here to concatenate a run of un-identical byte[]
                    count++; 
                }      
                
                //if loop if successive elments are identical
                if(replicate==true){
                    d_count=((-1*d_count)+1);
                    replicate=false;           
                    rtn_val[array_count]=(byte)d_count;
                    array_count++;
                    rtn_val[array_count]=inpByte[count];
                    array_count++;                    
                }       
          
                //loop here if successive values are not identical
                   if(replicate==false && temp.length()!=0){
                    d_count=temp.length()-1;  
                    rtn_val[array_count]=(byte)d_count;
                    array_count++;  
                    System.out.println("22222 " +temp);
                    rtn_val[array_count]=Byte.parseByte(temp);
                    array_count++;
                    temp="";//Now you have the literalRun, set it to null for next iteration                    
                    replicate=true;
                    count--; //needed to offset the count++ in 2nd while Loop
                }                
            }
            return rtn_val;
        }
 
public static void main(String[] args) throws Exception{
             
             RunLengthEncoding RLE = new RunLengthEncoding();
             String example="1%16%22%33%111";
             String example2="123111167888321555";
             byte[] example3=example2.getBytes();
             byte[] byteVal=RLE.encodeBytes(example3);//Leads to error
             System.out.println("byte vals "+byteVal); 
             	}

[Eranga]

Byte range from -128 to 127. You cannot hold such a large value in a byte variable.

[jav2000x]

Hi Eranga,

Ok - so what would be your suggestion - ie what should I do?

[Eranga]

Set you value in between that range. You may change your implementation.

[Tolls]

temp+=inpByte[count];

You're concatentaing a load of bytes here for some unknown reason...but this is why you're ending up with an over-large number.

If this is what's actually required then I don't see how you can expect this to be parseable into a byte.

Take the following byte[]...byte[0] = 99, and byte[1] = 12.
That line of code above (if I've read this correctly) will give you a temp of "9912", which you then attempt to turn into a byte.

[Eranga]

Separating could be a good solution, based on our OPs' requirement. I'm lazy to go through such a long code. :(