Help reading a text file.

[Kristoba]

Hi, I'm new here and I'm having some trouble with a java program.

I have to read a text file (The user provides the name). The program must follow these rules as well.

The first rule is that a word consists of what the next() method of the Scanner class will return. The next() method returns a String that consists of all the characters in the input up to, but not including, the next “whitespace character”, where blank spaces, tabs, and newline characters are the whitespace characters.

The second rule: If the word has a single- or double-quotation mark as the first character of the word, remove it.

The third rule: Look at the last character of the word. If this last character is any one of •single-quotation mark, double-quotation mark, semi-colon, colon, period, comma, hyphen, exclamation point, question mark, remove it.


So far i have this

public class Trimming
{
public static void man(String [] args) throws IOException
{
File inputFile = new File( "Sample.txt" );
Scanner fileScan = new Scanner( inputFile );
int number = fileScan.nextInt();


Any suggestions/help?

[PhHein]

What?! :confused:

[Kristoba]

That is exactly what i am thinking haha. So what i basically have to do is print each word to a line, excluding special punctuation.

[PhHein]

So, start with just one line and get that sorted first:

String line = "this \'is\' a \"line\" !of! the $file$"";
// do some magic here

Output:
this
is
a
line
of
the
file

The first thing that comes to mind is String.split().

[Kristoba]

Okay, so how exactly would i be able to get the words in in the text file to appear in the program. This is the only problem i am having. :) I'm using Scanner of course.

Say Name.txt is:

hello my name is John.

Output would appear exactly as what you showed.

[PhHein]

Uhm, using the nextLine() method from Scanner? I thought that would be obvious from the API.