simple histogram

[heartysnowy]

Hi , I would like to construct the simple histogram with symbols (e.g #or % or *).. based on the user integer input.. (input: 4 2 3), and i would like to display in this way.

+
+ +
+ + +
+ + + <---- histogram displayed with symbol

4 2 3 <---inputs (the number of input is fixed in this case)

Can you help me in how to display those symbols side by side.(in a histogram format), I am stuck when i tried to combine all the symbols together. My codes just display them in 1 vertical line instead of displaying on multiple vertical lines. below is my code. Thanks in advance.

import java.util.Scanner;
public class histogram {
        
   
    public static void main(String[] args) {
        int num1,num2,num3,num4;
        
        
        Scanner sc = new Scanner (System.in);
        
        System.out.print("Enter thhe numbers: ");
        num1 = sc.nextInt();
        String ss1 = genPattern(num1);
        num2 = sc.nextInt();
         String ss2 = genPattern(num2);
        num3 = sc.nextInt();
         String ss3 = genPattern(num3);
        num4 = sc.nextInt();
         String ss4 = genPattern(num4);
        
   		    
    
        	System.out.println(ss1   + ss2   + ss3  + ss4);
    }
    public static String genPattern(int number){
    
    	String msg= "";
    	String as = "+";
    	for (int i= 1; i<=number; i++){
        
        	 msg=msg+ as + "\n" ;

        	 		}
        
        return msg;
}
}

[al_Marshy_1981]

I am sure there are more elegant solutions to this but here is my solution. By the way I really enjoyed figuring it out :D

import java.util.Scanner;
import java.lang.Math;
public class Histogram {
        
   
    public static void main(String[] args) {
        int num1,num2,num3,num4;
        
        //rows will be determined by the highest number entered
        int rows;
        
        Scanner sc = new Scanner (System.in);
       
        System.out.print("Enter thhe numbers: ");
        num1 = sc.nextInt();
        rows=num1;
        String ss1 = genPattern(num1);
        
        num2 = sc.nextInt();
        rows=Math.max(num1, num2);
         String ss2 = genPattern(num2);
        
        num3 = sc.nextInt();
        if(rows<num3)
        {
        	rows=num3;
        }
         String ss3 = genPattern(num3);
        
        num4 = sc.nextInt();
        if(rows<num4)
        {
        	rows=num4;
        }
         String ss4 = genPattern(num4);
         
         
         System.out.println("Rows: "+rows);
         //use 2d character array to store the pattern
         Character display[][]=new Character [rows][4];
         
         int ss1Index=0,ss2Index=0,ss3Index=0,ss4Index=0;
         
         //get ss1 pattern and let column 0 of display hold its contents
         for(int i=rows-1;i>=0;i--)
         {
        	 if(ss1Index<ss1.length()){
        	 display[i][0]=ss1.charAt(ss1Index);
        	 ss1Index++;
        	 }
        	 else{
        		 display[i][0]=' ';
        	 }
         }
        
         //get ss2 pattern and let column 1 of diplay hold its contents
         for(int i=rows-1;i>=0;i--)
         {
        	 if(ss2Index<ss2.length()){
        	 display[i][1]=ss2.charAt(ss2Index);
        	 ss2Index++;
        	 } else{
        		 display[i][1]=' ';
        	 }
         }
         
       //get ss3 pattern and let column 2 of diplay hold its contents
         for(int i=rows-1;i>=0;i--)
         {
        	 if(ss3Index<ss3.length()){
        	 display[i][2]=ss3.charAt(ss3Index);
        	 ss3Index++;
        	 } else{
        		 display[i][2]=' ';
        	 }
         }
         
       //get ss4 pattern and let column 3 of diplay hold its contents
         for(int i=rows-1;i>=0;i--)
         {
        	 if(ss4Index<ss4.length()){
        	 display[i][3]=ss4.charAt(ss4Index);
        	 ss4Index++;
        	 } else{
        		 display[i][3]=' ';
        	 }
         }
         
         //display the histogram
         for(int i=0;i<rows;i++)
         {
        	 for(int j=0;j<4;j++)
        	 {
        		 if(display[i][j]==null)
        		 {
        			 System.out.print(" ");
        		 }else{
        		
        			 System.out.print(display[i][j]);
        		 }
        		 }
        	 System.out.println();
         }
    }
    	

	
    public static String genPattern(int number){
    
    	String msg= "";
    	String as = "+";
    	for (int i= 1; i<=number; i++){
        	 msg=msg+ as ;
        }
        
        return msg;
}
}

hope this is helpful

[heartysnowy]

thanks marshy for ur work ..glad that u enjoy solving my prob :D..

Could there be other way to solve it w/o using an array? I am doing the school work here and we aren't allowed to use array for this case ;(... i know beggar can't b chooser but I really need other way around...