simple histogram

Hi , I would like to construct the simple histogram with symbols (e.g #or % or *).. based on the user integer input.. (input: 4 2 3), and i would like to display in this way.

+
+ +
+ + +
+ + + <---- histogram displayed with symbol

4 2 3 <---inputs (the number of input is fixed in this case)

Can you help me in how to display those symbols side by side.(in a histogram format), I am stuck when i tried to combine all the symbols together. My codes just display them in 1 vertical line instead of displaying on multiple vertical lines. below is my code. Thanks in advance.

Code:

---

import java.util.Scanner;
public class histogram {
       
 
    public static void main(String[] args) {
        int num1,num2,num3,num4;
       
       
        Scanner sc = new Scanner (System.in);
       
        System.out.print("Enter thhe numbers: ");
        num1 = sc.nextInt();
        String ss1 = genPattern(num1);
        num2 = sc.nextInt();
        String ss2 = genPattern(num2);
        num3 = sc.nextInt();
        String ss3 = genPattern(num3);
        num4 = sc.nextInt();
        String ss4 = genPattern(num4);
       
                     
   
                System.out.println(ss1  + ss2  + ss3  + ss4);
    }
    public static String genPattern(int number){
   
            String msg= "";
            String as = "+";
            for (int i= 1; i<=number; i++){
       
                msg=msg+ as + "\n" ;

                                }
       
        return msg;
}
}

---

I am sure there are more elegant solutions to this but here is my solution. By the way I really enjoyed figuring it out :D

Code:

---


import java.util.Scanner;
import java.lang.Math;
public class Histogram {
       
 
    public static void main(String[] args) {
        int num1,num2,num3,num4;
       
        //rows will be determined by the highest number entered
        int rows;
       
        Scanner sc = new Scanner (System.in);
     
        System.out.print("Enter thhe numbers: ");
        num1 = sc.nextInt();
        rows=num1;
        String ss1 = genPattern(num1);
       
        num2 = sc.nextInt();
        rows=Math.max(num1, num2);
        String ss2 = genPattern(num2);
       
        num3 = sc.nextInt();
        if(rows<num3)
        {
                rows=num3;
        }
        String ss3 = genPattern(num3);
       
        num4 = sc.nextInt();
        if(rows<num4)
        {
                rows=num4;
        }
        String ss4 = genPattern(num4);
       
       
        System.out.println("Rows: "+rows);
        //use 2d character array to store the pattern
        Character display[][]=new Character [rows][4];
       
        int ss1Index=0,ss2Index=0,ss3Index=0,ss4Index=0;
       
        //get ss1 pattern and let column 0 of display hold its contents
        for(int i=rows-1;i>=0;i--)
        {
                if(ss1Index<ss1.length()){
                display[i][0]=ss1.charAt(ss1Index);
                ss1Index++;
                }
                else{
                        display[i][0]=' ';
                }
        }
       
        //get ss2 pattern and let column 1 of diplay hold its contents
        for(int i=rows-1;i>=0;i--)
        {
                if(ss2Index<ss2.length()){
                display[i][1]=ss2.charAt(ss2Index);
                ss2Index++;
                } else{
                        display[i][1]=' ';
                }
        }
       
      //get ss3 pattern and let column 2 of diplay hold its contents
        for(int i=rows-1;i>=0;i--)
        {
                if(ss3Index<ss3.length()){
                display[i][2]=ss3.charAt(ss3Index);
                ss3Index++;
                } else{
                        display[i][2]=' ';
                }
        }
       
      //get ss4 pattern and let column 3 of diplay hold its contents
        for(int i=rows-1;i>=0;i--)
        {
                if(ss4Index<ss4.length()){
                display[i][3]=ss4.charAt(ss4Index);
                ss4Index++;
                } else{
                        display[i][3]=' ';
                }
        }
       
        //display the histogram
        for(int i=0;i<rows;i++)
        {
                for(int j=0;j<4;j++)
                {
                        if(display[i][j]==null)
                        {
                                System.out.print(" ");
                        }else{
                       
                                System.out.print(display[i][j]);
                        }
                        }
                System.out.println();
        }
    }
           

       
    public static String genPattern(int number){
   
            String msg= "";
            String as = "+";
            for (int i= 1; i<=number; i++){
                msg=msg+ as ;
        }
       
        return msg;
}
}

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hope this is helpful

thanks marshy for ur work ..glad that u enjoy solving my prob :D..

Could there be other way to solve it w/o using an array? I am doing the school work here and we aren't allowed to use array for this case ;(... i know beggar can't b chooser but I really need other way around...