How to handle ArrayIndexOutOfBoundsException

Hi all,

I am trying to find a way to handle an ArrayIndexOutOfBoundsException.

Code:

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int [] plegma = new int[10];
int x = plegma[11]);

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this will give an exception. Is there a way (maybe try-catch) to set the variable to the previous code to 0 i.e every time an index is out of bound to set it to 0?

Thank you for your help.

Quote:

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Originally Posted by 3xpr1ment

Hi all,

I am trying to find a way to handle an ArrayIndexOutOfBoundsException.

Code:

---

int [] plegma = new int[10];
int x = plegma[11]);

---

this will give an exception. Is there a way (maybe try-catch) to set the variable to the previous code to 0 i.e every time an index is out of bound to set it to 0?

Thank you for your help.

---

No, don't catch it. The secret here is to write code that is smart enough not to run into this problem. If you loop through an array for instance, use the array's length as the stopping point.

Thanks for your help Fubarable!

Quote:

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Originally Posted by Fubarable

If you loop through an array for instance, use the array's length as the stopping point.

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And ... the stopping point must be 1 smaller than the array's length. so in a for loop check for < and not <=

for (int i=0; i < plegma.length; i++ {
yourcode;
}

at the beginning, this concept is a little confusing and needs getting used to. have fun.

Thank you j2me64. Actually I got a 2d matrix where the state of each element depends on the state of its neighbors . The elements on the borders have no neighbors from the one side.
I wanted to know what is the best practice (acquire good programming habits :)) in this case, to handle the exception or add an additional row, column on this side it and set the its state to 0.

I wouldn't use exception here or an extra row or column but rather use simple math to know when I'm at the boundaries and to not go beyond. Math.min and Math.max can be helpful. For instance look at post #16 here: http://www.java-forums.org/new-java/...tml#post106270

Quote:

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Originally Posted by 3xpr1ment

Thank you j2me64. Actually I got a 2d matrix where the state of each element depends on the state of its neighbors . The elements on the borders have no neighbors from the one side.
I wanted to know what is the best practice (acquire good programming habits :)) in this case, to handle the exception or add an additional row, column on this side it and set the its state to 0.

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Try both alternatives: one version where you check whether or not your in a corner or on an edge and another where you've added two rows and two columns around the actual values of the matrix; note that you have to adjust your loop bounds to:

Code:

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for (int i= 1; i < array.length-1; i++) ...

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... and see which version you like most (I like the additional rows/columns trick most because there is no bounds checking needed).

kind regards,

Jos