How to convert a String into an Hexadecimal ?

[ze snow]

Hi!

I have a String which represents a hexadecimal number (e.g. "5FA2"). Ideally, I would like to convert this String into an int (e.g. 0x5FA2), is there a quick way to do this ?

I can't use the method "Integer.parseInt()" since my String represents an hexadecimal and not a decimal.

Thanks in advance!

[r035198x]

Read the API specs for the Integer class. There is another Integer.parseInt method that you will find interesting.

[JosAH]

Hi!

I have a String which represents a hexadecimal number (e.g. "5FA2"). Ideally, I would like to convert this String into an int (e.g. 0x5FA2), is there a quick way to do this ?

I can't use the method "Integer.parseInt()" since my String represents an hexadecimal and not a decimal.

Thanks in advance!

You shouldn't have stopped reading the API documentation after you've found a method that doesn't apply. There's also an overloaded method that can do the job.

kind regards,

Jos

[ze snow]

Thanks guys!

Looks like the method Integer.decode() is working :-)

[JosAH]

Thanks guys!

Looks like the method Integer.decode() is working :-)

decode( ... ) gives you an Integer, not an int; auto(un)boxing will help you but still an additional Integer object was created (ignoring the fact of caching some Integers here). Better use the overloaded parse( ... ) method. Read the API documentation for the Integer class (again).

kind regards,

Jos

[ze snow]

Sorry, I just missed this other parse method.
Indeed, that works even better, saves 1-2 lines :-)


Thanks again JosAH!

[r035198x]

Sorry, I just missed this other parse method.
...
Thanks again JosAH!

You also missed my reply.


r035198x<----jealous

[ze snow]

Oops
Sorry r035198x, thank you too, you were first!