Working with float

[dardar]

i using a vector of floating points.
when i print the vector the numbers looks like 2.2064104561

how do i "chop" them to something like 2.206 or so?

thank you

[Lil_Aziz1]

System.out.printf(); or System.out.format(); works great

double x = 4.215312531235;
System.out.printf("%.3f",x);

Output:

4.215

EDIT: System.out.printf() or System.out.format() will round. If you want to floor it (meaning round down) , subtract 0.5 from the float var and then do the System.out.printf() or System.out.format().

[dardar]

let me rephrase my problem.

I'm using the line
double ans = Math.random();

ans looks like 2.01656717611 (ugly....)
is there a way after I'm using the random method to "chop" the number to 2.01

the printing is not the issue. i need to work with "relativity" large numbers.

[Tolls]

Why do you need to truncate them like that?

[dardar]

it's hard to explain why......it's part of an algirthm i'm using.

someone told me the Class Double has a method to do that but i cant find it.

[Tolls]

They might mean BigDecimal. That allows you to faff with scales, which is what you want I think.

[StormyWaters]

You could always do something like this...

float fValue = 2.01656717611f;
fValue =     ((int)(fValue * 100)) / 100f;

[Tolls]

Is accuracy important? Just asking, because of the inevitable limitations of floating points in representing decimal fractions.

[dardar]

i dont care about accuracy at all.