my java assigment problem!

[lieni]

Hi ! I have a Java assigment which consists of making a program for a telephone directory. I have this piece of program for which in the line where there is this.Surname it is giving me an error which is saying unreachable statement. Here is the program:

public boolean equals(Contact other)
{
return(other.Name.equals(this.Name));
return(other.Surname.equals(this.Surname));
return(other.ID.equals(this.ID));
return(other.Tel == this.Tel);
return(other.Town.equals(this.Town));
}
can you help me please by sending me an email on lieni_elaine@hotmail.com?
Thank you.

[r035198x]

You need to revise your notes on the return keyword to understand what it does. That should let you know why the compiler finds it strange that you have some code after your return.
Also read
Overriding the equals and hashCode methods - Java insights

[turanan]

Just use this piece instead

public boolean equals(Contact other)
{
    if(other.Name.equals(this.Name) &&
        (other.Surname.equals(this.Surname) &&
        (other.ID.equals(this.ID) &&
        (other.Tel == this.Tel) &&
        (other.Town.equals(this.Town)) {
        return true;
    }
    return false;
}

[lieni]

thank you for your suggestions!:D

[lieni]

Hey ! thanks again for the suggestions it worked! but now i have another problem(apart from million of them in this assigment:rolleyes:) now the error is: cannot find symbol method compareto(java.lang.String);(btw the iehor is instead of other). Please can you help me once again? Thank you. This is the code:



public int compareto(Contact iehor){
return this.surname.compareto(Contact.this .surname);
}

[Newbie666]

I think the class needs to implement Comparable interface, and the method is named compareTo() not compareto(), check out the Comparable interface in the API

[lieni]

but the compiler does not stop there it stops line after where there is the return.

[Fubarable]

Show your code with code tags, the exact error message, and indicate with comments the line that causes the error to occur.

Luck.

[lieni]

public int compareto(Contact iehor){
return this.surname.compareto(Contact.this .surname); //here it is giving me an error
}

the error is: cannot find symbol-method compareto(java.lang.String)
is it more clear?

[Fubarable]

public int compareto(Contact iehor){
return this.surname.compareto(Contact.this .surname); //here it is giving me an error
}

the error is: cannot find symbol-method compareto(java.lang.String)
is it more clear?

You're still missing the code tags here making it harder to read your code. Please read my signature below for more on this.

Other problems here:
1) Java is case sensitive and so compareto is not the same as compareTo. Check out the Java API to see which to use.
2) Your compareTo method gets a Contact object, iehor, and yet your method body completely ignores this parameter. Myself, I would compare the current object's surname (this.surname) with that of the parameter's.

[lieni]

hi I have other problem... i have this piece of problem for which the error is incompatible types-found Contact[] but expected Contact... this is the code:

File inputFile = new File ("agenda.dat");
FileInputStream downStream = new FileInputStream(inputFile);
ObjectInputStream inObjectStream = new ObjectInputStream(downStream);


pos = Utilities.search(conId,myContact);
Contact mycontact[]= null;


//to load whole arraylist
try{
c = (Contact[]) inObjectStream.readObject(); // THIS IS WHERE THE ERROR IS.
}
catch (Exception e)
{System.out.println("\nSomething went wrong when loading file: "+e.getMessage());}//end catch


int n = Contact.size;
System.out.println("Stored contacts\' Details include:\n");
for (int i = 0 ; i <n; i++){
System.out.println("Name: "+ Contact[i].getName());
System.out.println("Surname: "+ Contact[i].getSurname());
System.out.println("Town: " +Contact[i].getTown());
System.out.println("ID: " +Contact[i].getId());
System.out.println("Telephone number: " +Contact[i].getTel());
System.out.println();
}//end for
inObjectStream.close();

break;


Can you help me pls?
Thank you for the support.

[collin389]

Hi, most likely, readObject() will only read one object at a time, not a whole array of them, Also, i don't think you can write a whole array becuase you have to be writing a serializable Object, and an array is not serializable.

[Tolls]

What is 'c'?
That error is a compiler error isn't it? In which case 'c' is presumably a Contact and not a contact[].

[lieni]

we are using an arraylist not an array . so it is serializable. c is declared as Contact c = null; in the main program. this piece of program is located in the main program as a case for which it reads entries from a file. what do you think that particular line will become?

[lieni]

10q tolls that solved my problem :D and collin thanks for pointing out your suggestion:D

[JosAH]

Hi, most likely, readObject() will only read one object at a time, not a whole array of them, Also, i don't think you can write a whole array becuase you have to be writing a serializable Object, and an array is not serializable.

This is incorrect: arrays are Serializable if their element types are and an ObjectOutputStream can write entire arrays in one sweep.

kind regards,

Jos

[collin389]

Oh, good to know.