swapping elements of vector

[sara12345]

hello
I need to swap elements of vector but without redunducy. for example swapping elements 1 with 2 is the same as swapping element 2 with 1 so I don't want to save the second result I want to save it only one time
my code is the following :

			for( int x=0;x<v1size();x++)	{    	    
			 for ( int w=0;w< v1.size();w++){
				 Collections.swap(v1, x, w);

but the above code will swap with redunducy:(

[pbrockway2]

One way of calling each of the (size*(size+1))/2 distinct pairs of list indices would be

for(int x = 0; x<v1.size(); x++) {
    for(int w = x; w< v1.size();w++) {

ie swap an index position with those to its right.

Do you realise that once you call Collections.swap() the index positions now refer to different objects? That's why I said that the code above was one way of doing it. If you do all the (size*(size+1))/2 swaps in a different order you will end up with a different result. And you haven't described the result you want!

As an example of this, consider a list of three objects:

A B C

There are exactly three swaps possible (0,1)=(1,0) (0,2)=(2,0) (1,2)=(2,1). If we follow the "swap to the right" rule we get

A B C (0,1) --> B A C
B A C (0,2) --> C A B
C A B (1,2) --> C B A

But if we do the same three "non redundant" swaps in a different order we get

A B C (1,2) --> A C B
A C B (0,1) --> C A B
C A B (0,2) --> B A C