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About LinkBacks- 12-20-2009, 10:09 AM #1
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how to convert string to int in guess number game in jsp
Iam new to jsp and trying to get input from user and then check either the input match with the number provided by the programmer. here is my code :
<form method="get">
Guess number :
<input type="text" name="n" />
<%
String a=63;
String n = request.getParameter("n");
int g=Integer.parseInt("n");
if(g==a)
{
out.println("you won");
}
else
{
out.println("wrong guess");
}
%>
</form>
but i am having errors which are as follows :
type Exception report
message
description The server encountered an internal error () that prevented it from fulfilling this request.
exception
org.apache.jasper.JasperException: Unable to compile class for JSP:
An error occurred at line: 17 in the jsp file: /guess number.jsp
Type mismatch: cannot convert from int to String
14: <input type="text" name="n" />
15:
16: <%
17: String a=63;
18: String n = request.getParameter("n");
19: int g=Integer.parseInt("n");
20: if(g==a)
An error occurred at line: 20 in the jsp file: /guess number.jsp
Incompatible operand types int and String
17: String a=63;
18: String n = request.getParameter("n");
19: int g=Integer.parseInt("n");
20: if(g==a)
21: {
22: out.println("you won");
23: }
Stacktrace:
org.apache.jasper.compiler.DefaultErrorHandler.jav acError(DefaultErrorHandler.java:92)
org.apache.jasper.compiler.ErrorDispatcher.javacEr ror(ErrorDispatcher.java:330)
org.apache.jasper.compiler.JDTCompiler.generateCla ss(JDTCompiler.java:439)
org.apache.jasper.compiler.Compiler.compile(Compil er.java:334)
org.apache.jasper.compiler.Compiler.compile(Compil er.java:312)
org.apache.jasper.compiler.Compiler.compile(Compil er.java:299)
org.apache.jasper.JspCompilationContext.compile(Js pCompilationContext.java:586)
org.apache.jasper.servlet.JspServletWrapper.servic e(JspServletWrapper.java:317)
org.apache.jasper.servlet.JspServlet.serviceJspFil e(JspServlet.java:342)
org.apache.jasper.servlet.JspServlet.service(JspSe rvlet.java:267)
javax.servlet.http.HttpServlet.service(HttpServlet .java:717)
--------------------------------------------------------------------------------
I will be thankful if anyone can provide me the solution of this code or can edit my code correctly.. waiting for replies thx in advance..!!
- 12-20-2009, 11:36 AM #2gcampton Guest
int a;
String b="69";
a = Integer.parseInt(b);
the variables don't need inverted commas, only string literals do
- 12-20-2009, 02:57 PM #3
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thx for the help but still iam having errors i have edited my code by makin 2 pages one is number.jsp and other is check.jsp and the code is as follows :
number.jsp :
<form method="get" action="check.jsp">
<input type="text" name="n" />
<input type="submit"/>
</form>
check.jsp :
<body>
<%
int a=63;
String n = request.getParameter("n");
int g=Integer.parseInt("n");
if(g==a)
{
out.println("you won");
}
else
{
out.println("wrong guess");
}
%>
</body>
now the errors are as follows :
type Exception report
message
description The server encountered an internal error () that prevented it from fulfilling this request.
exception
org.apache.jasper.JasperException: An exception occurred processing JSP page /check.jsp at line 13
10: <%
11: int a=63;
12: String n = request.getParameter("n");
13: int g=Integer.parseInt("n");
14:
15: if(g==a)
16: {
Stacktrace:
org.apache.jasper.servlet.JspServletWrapper.handle JspException(JspServletWrapper.java:505)
org.apache.jasper.servlet.JspServletWrapper.servic e(JspServletWrapper.java:416)
org.apache.jasper.servlet.JspServlet.serviceJspFil e(JspServlet.java:342)
org.apache.jasper.servlet.JspServlet.service(JspSe rvlet.java:267)
javax.servlet.http.HttpServlet.service(HttpServlet .java:717)
root cause
java.lang.NumberFormatException: For input string: "n"
java.lang.NumberFormatException.forInputString(Unk nown Source)
java.lang.Integer.parseInt(Unknown Source)
java.lang.Integer.parseInt(Unknown Source)
org.apache.jsp.check_jsp._jspService(check_jsp.jav a:66)
org.apache.jasper.runtime.HttpJspBase.service(Http JspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet .java:717)
org.apache.jasper.servlet.JspServletWrapper.servic e(JspServletWrapper.java:374)
org.apache.jasper.servlet.JspServlet.serviceJspFil e(JspServlet.java:342)
org.apache.jasper.servlet.JspServlet.service(JspSe rvlet.java:267)
javax.servlet.http.HttpServlet.service(HttpServlet .java:717)
- 12-20-2009, 03:22 PM #4
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I know some Java but know no JSP, but I think that gcampton was suggesting that you change this:
to this:Java Code:10: <% 11: int a=63; 12: String n = request.getParameter("n"); 13: int g=Integer.parseInt("n"); 14:
The n variable (a terribly non-descriptive variable name, btw) holds a number String, and you want to parse this string via parseInt(n). If you try parseInt("n") you're trying to parse a letter, not a variable, and unless you're parsing hex numbers (by calling an overload of the parseInt method and setting the method's radix) and your letters are less than f, this makes no sense.Java Code:10: <% 11: int a=63; 12: String n = request.getParameter("n"); 13: int g=Integer.parseInt(n); // no quotes here 14:
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