Help with JOptionPane

[SwEeTAcTioN]

So this is the first time ive ever used JPanes so i have some questions

first is how do i do math with them?
it just concatenates the 2 numbers

Second is i saw an example and they used a buffer reader
Why?

And third can someone help me with this code it just concatenates the two numbers and ive tryed everything

All help is appreciated:)

import java.io.*;
import javax.swing.*;
import java.util.Random;


public class CasinoGame{


  
public static void main(String[] args)throws IOException{
	
	
    String say;
	String say2;
	String say3;
    say= JOptionPane.showInputDialog(null, "Type in 1 number");
	say2= JOptionPane.showInputDialog(null, "Type in 1 more number");
	say3=say+say2;
	JOptionPane.showMessageDialog(null, "The sum of the two numbers is "+say3);
	
	
}
}

[camickr]

So this is the first time ive ever used JPanes so i have some questions

I have a question to, whats a "JPane"?

first is how do i do math with them?

Use Integer.parseInt(...) to get an int value you can use in your math formulas

Second is i saw an example and they used a buffer reader, Why?

I have no idea why?

And third can someone help me with this code it just concatenates the two numbers

How is this different than the first question?

[Fubarable]

A showInputDialog returns a String, and this is important because if you do this:

"2" + "2"

you'll get "22", not what you want.

To add, you must use numbers, and to get numbers from a String, you must parse. If I were you, I'd look into use the Integer.parseInt(...) method to parse each String into a number and then add the number.

[Eranga]

String concatenation have different meanings in different cases. For an example following line of code,

System.out.println(1 + 1);

It'll give 2 as the output. But in your case compiler seen them as Strings, simply concatenate.

Java(tm) String Operations

[camickr]

String concatenation have different meanings in different cases. For an example following line of code,

String concatenation is always string concatenation.

System.out.println("1" + "1") displays "11" because you are concatenating 2 strings.

System.out.println(1 + 1) displays 2 because you are adding two integers.

System.out.println(1 + "1") displays "11" because the integer 1, is converted to a string and string concatenation is done.

[Eranga]

String concatenation is always string concatenation.

System.out.println("1" + "1") displays "11" because you are concatenating 2 strings.

System.out.println(1 + 1) displays 2 because you are adding two integers.

System.out.println(1 + "1") displays "11" because the integer 1, is converted to a string and string concatenation is done.

I think you've misunderstand my comment. I'm talking about the logical meaning of that. As your examples in first line of code, deals with strings, you define them as it is. In the second line it's just and an addition of integer values, and the last on is just mixing them. Same thing I'm pointed, may be the explanation not clear to you.

[SwEeTAcTioN]

So im still not understanding im using the parseInt an i dont think im using it right

Heres my code

All help is appreciated:)

public class CasinoGame{


  
public static void main(String[] args)throws IOException{
	
	
    String say;
	String say2;
	String say3;
	
    say= JOptionPane.showInputDialog(null, "Type in 1 number");
    Integer.parseInt(say);
	say2= JOptionPane.showInputDialog(null, "Type in 1 more number");
	Integer.parseInt(say2);
	say3=say+say2;
	JOptionPane.showMessageDialog(null, "The sum of the two numbers is "+say3);
	
	
}
}

[Eranga]

To which you refer this,

Integer.parseInt(say2);

[SwEeTAcTioN]

What?:confused:

[camickr]

Did you read the API to see what value is returned from the parseInt() method?

Did you search the forum or the web to find examples that use the method in question?

Learn how to do some basic problem solving on your own. You learn more and its faster when you don't have to wait and hope someone spoonfeeds you the code.

[Eranga]

Here is an simple explanation.

    // Declaring two String variables (objects)
    String say, say2;

    // Declaring two integer variable
    int val1, val2;

    // Get the user input
    say= JOptionPane.showInputDialog(null, "Type in 1 number");
    say2= JOptionPane.showInputDialog(null, "Type in 1 more number");

    // Converting those strings into integer values
    val1 = Integer.parseInt(say);
    val2 = Integer.parseInt(say2);

    // Display the result
    JOptionPane.showMessageDialog(null, "The sum of the two numbers is " + (val1 + val2));

[SwEeTAcTioN]

im pretty new whats API?

[Eranga]

im pretty new whats API?

It's the explanation of all the methods and attributes use in Java.

Java Platform SE 6