Input technique for unknown lines of input

[ducreative]

I have a problem with input techniques from user. Suppose user can feed up program 3 lines as:

Department of Computer science
and 
engineering University of Dhaka

But our programmer does not know how many lines are there and we have to process one line and then to next line. After reading all the lines i have to display all inputs accordingly. Output should be

Department of Computer science
and 
engineering University of Dhaka

Here is my program

import java.util.ArrayList;
import java.util.Iterator;
import java.util.Scanner;

public class InputTechnique {
    public static void main(String args[]){
         Scanner scan = new Scanner(System.in);
         ArrayList<String> aList = new ArrayList<String>();
         while(scan.hasNextLine()){
             aList.add(scan.nextLine());
         }
         Iterator it = aList.iterator();
         while(it.hasNext())
             System.out.println(it.next());
    }
}

My program hangs on first while loop. How can solve this problem?

[Fubarable]

How do you know when the user is done inputting text? Do they send a blank line?

[Tolls]

What do you mean by "it hangs"?
It'll accept your input, so it's not hanging...you just haven't given it an exit.

[ducreative]

i mean it cannot break the first while loop and continue taking inputs from user.
User can feed blank lines as

hello
i am new to

this forum

Output should be

hello
i am new to

this forum

Thanks.

[Tolls]

So, as Fubarable has asked, and (I think) was pointed out in the thread you tried to hijack, how does the user exit?

[ducreative]

yes, my question is how does the program terminate? Is there any process to solve this. I need this requirement for solving a UVA online judge problem, and if i am failed to make you understand what i am trying to say, just visit uva online judge and the problem ID is 10815[Andy's First Dictionary].

Thanks

[Tolls]

OK...step back then...how do you want the user to say they've entered enough?

In the real world I have never written a command line user input program...at least not in the past 15+ years. So, how do you want them to inform the program they have finished?

Fubarable has given an option in his post, and there were one or two on the other thread.

[ducreative]

How can i find the End Of Files? Would you like to mention the technique.

[Tolls]

What end of file?
It's user input.
You have to decide what the user needs to enter to say they've finished.

There is no "technique"...what does the user have to do to say they've finished entering data?

[ducreative]

Ok, Thanks.

[Tolls]

Right, no problem.
Do you now understand what you have to do to get this to work?

[ducreative]

Yes, thanks a lot Tolls. I have to take the input from files rather than console.

[Fubarable]

At least for me, your creeping requirements have confused me greatly and continue to confuse me. In your first post, you mention nothing about files and fact state this:

I have a problem with input techniques from user. Suppose user can feed up program 3 lines as:

and in your code you have

Scanner scan = new Scanner(System.in);

With a Scanner that is constructed with System.in, you show that the program will take input from the console.

So I have to ask, what the heck is going on? What are your real requirements here and why are you changing things?

If you confuse your questions you will get nothing but confusing answers.

[Tolls]

Yes, thanks a lot Tolls. I have to take the input from files rather than console.

As Fubarable says, that wasn't your requirement at the start. If you have a requirement to take input from the user then that's what you should be writing.

[RamyaSivakanth]

Hi,
U just take the input
"y" or "n" from the user .If they say "n" just come out.

-Regards
Ramya

[ducreative]

Okay, i am explaining now. The first thing is that i am new in java. Actually i like C++. Look at this code bellow

#include<iostream>
#include<cstring>
using namespace std;

struct x{
	char array[100];
}sample[100];
int main(){
	freopen("input.txt", "r", stdin);
	char input[101];
	int indexx = -1;
	while(gets(input)){
		strcpy(sample[++indexx].array, input);
	}
	
	for(int i = 0; i <= indexx; i++)
		cout << sample[i].array;
	return 0;
}

In the above program all inputs are taken from the file. But if we close the freopen function as

//freopen("input.txt", "r", stdin);

all the inputs are taken from console and in msdev when i use ctrl + z that means end of file and we ready to jump for loop and execute output. I want to know the same things i posted before in my thread.

i wanted to write this code in java as

import java.util.ArrayList;
import java.util.Iterator;
import java.util.Scanner;

public class InputTechnique {
    public static void main(String args[]){
         Scanner scan = new Scanner(System.in);
         ArrayList<String> aList = new ArrayList<String>();
         while(scan.hasNextLine()){
             aList.add(scan.nextLine());
         }
         Iterator it = aList.iterator();
         while(it.hasNext())
             System.out.println(it.next());
    }
}

I want to replace this C++ code to java. In solving problem UVA online judge the "fropen()" function should be closed before submitting the solution.

Now i think, you understand my words what i am trying to say. Now give me a solution.

[Tolls]

And this is the problem.
Java is not C++.
You cannot simply take code from one language and expect to turn it into another one without actually learning the language itself.

I am, however, not going to give you the solution. There is no "freopen" function in Java.

Scanner is not freopen.
You need to learn how Scanner works...especially with System.in.
As has been said several times on this thread, you need to decide what value the user has to enter (and it will involve <enter> since that's how nextLine works) to indicate they have finished.