Hello

i am trying to make a recursive method that take a decimal number and convert it into its binary number. i think there will be two base cases that remainder is one or zero .can anyone help me further with simple solution

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- 07-24-2009, 10:25 AMAnindoconverting decimal to binary value using recursion in java
Hello

i am trying to make a recursive method that take a decimal number and convert it into its binary number. i think there will be two base cases that remainder is one or zero .can anyone help me further with simple solution - 07-24-2009, 09:13 PMjavamaddSimpler way to do the same
import java.util.Scanner;

public class toBinary {

/**

* @author : javamadd

*/

public static void main(String[] args) {

int num;

System.out.println("enter the decimal number");

Scanner scanboy = new Scanner(System.in);

num = scanboy.nextInt();

System.out.print("The decimal number is " + num);

String binary = Integer.toBinaryString(num);

System.out.print(" And the corresponding Binary is ");

System.out.print( ""+ binary);

}

} - 07-25-2009, 03:28 AMEranga
@OP, what you mean by recursive method? Can you explain bit more clearly. What javamadd explain is straightforward, no any recursive process going on.

- 07-25-2009, 01:44 PMHardikReccursion method to convert decimal to binary.
hey here is the code :

class Binary

{

int a1,b1;

void convert(int a1)

{

b1 = a1 % 2;

if(a1 > 0)

{

convert(a1/2);

System.out.println("binary bits are = "+b1); //i think the result would you get reverse of the byte so u take care about it

}

}

}

class DECTOBIN

{

public static void main(String args[])

{

Binary obj = new Binary();

obj.a1 = Integer.parseInt(args[0]);

obj.convert(obj.a1);

}

}

Ok well. this is the code. But i didnt try it.