Invoking a superclass version of a overridden method

[CyberFrog]

Hi all,
I am currently going through an example on the above topic (see subject) and with this comes a snippet of code,

class Boxer extends Dog2 {
    public void printYourself () { 
     super.printYourself();  //Invoke the super class (Dog2)
                            //then do Boxer specific work here
     System.out.println("You have just printed your sub-method!!");
    }
}


public class Dog2{
    public void eat()  {}
    public void printYourself() {
     }
    public static void main(String [] args) {
        
    }

}

Now as far as I can see this example shows super being used to invoke an overridden method i.e. the Boxer method. I have added these print statements to emohasise what method is being used but it doesn't print, does anyone know how I can emphaises this example with these simple print statements? So that I print a statement when we use super

Thanks

[RamyaSivakanth]

Hi,
put S.O.P inside printYourself meth of Dog2 class to make sure that super is called

[CyberFrog]

Hi Ramya,

I have just attempted this but it doesn't print?

class Boxer extends Dog2 {
    public void printYourself () { 
        
     super.printYourself();  //Invoke the super class (Dog2)
                            //then do Boxer specific work here
     
    }
}


public class Dog2{
    public void eat()  {}
    public void printYourself() {
             System.out.println("You have just printed your supermethod!!");   
     }
    public static void main(String [] args) {

    }

}

Where in the printYpurself method does it go?

Sorry as you cann tell I am a beginner : )

[RamyaSivakanth]

Hi,
Here subclass extends the functionality of super class .So create an instance of Boxer.

So,inside the main method
1. create an instance of Boxer which is a subclass which got the inherited functionalty.

Boxer obj = new Boxer();

2.Then call obj.printYourself();