Exception question

[McChill]

I want to take a fully qualified class name as the program's argument. Then print out the superclasses of the class.

public class Check {

	
	public static void main(String[] args) {
		for(int i=0;i<args.length;i++)
		{
			try 
			{
				Class a = args[i].getClass();      //make a class object 
				while(a.getSuperclass() != null) 	//loop while it has a superclass
				{
					System.out.println(a.getSuperclass().toString() + "is a superclass of " + a.toString());
					a = a.getSuperclass(); 		
				}
			}
//			catch(ClassNotFoundException e) {			//compiler says the exception is never thrown here
				System.out.println("Sorry, that class was not found.");
			}
				
			}		
		
	}

}

It says the exception is never thrown. I'm not sure how to check (or write the code) to where I don't need to include a throw statement. I thought if the catch block is within the same method, throw exception is not needed.

[paul pasciak]

I'll assume that you need explaination of the concept voiced in this quote:

"I thought if the catch block is within the same method, throw exception is not needed"

This can be true, however, just making a try{}catch{} statement that you
specify to catch a particular Exception does not mean that code to create
such an Exception will magically appear within the try braces.

For example, change "ClassNotFoundException e" to "Exception e".
This will compile because some sort of exception can be thrown
by the code you put in the try braces.

Also, "NullPointerException e" will compile. You might be familiar
with this exception, and you probably can identify what in the
try braces will cause "NullPointerException" to be thrown.

You have two options:

Find a method that generates "ClassNotFoundException e" and
place it in your try braces.

or

Create your own test that throws "ClassNotFoundException e".

[azzaiel]

Try declaring a class that does not exist

example:

IdoNotExist thiswontwork = new IdoNotExist(); //this shoud generate a class not foud exemption (i hope)