ParseInt question

[McChill]

static int parseInt(String s)
Parses the string argument as a signed decimal integer.

public class Divider {
	
	public static void main(String args[])
	{
		try{
			System.out.println("Before divison");
			int i = Integer.parseInt(args[0]);
			int j = Integer.parseInt(args[1]);
			System.out.println(i/j);
			System.out.println("After divison");			
		}
		catch(ArithmeticException e) {
			System.out.println("Arithmetic Exception");
		}
		catch(ArrayIndexOutOfBoundsException e) {
			System.out.println("Array Index Out Of Bounds Exception.");
		}
		catch(NumberFormatException e) {
			System.out.println("Number Format Exception");
		}
		finally {
			System.out.println("Finally block");
		}
	}

}

If I put in, for example, "1" and "hey" the program gives me a number format exception. I thought parseint returned the string AS an int? If so, why does it give me an exception?

[masijade]

The "1" is okay, the "hey" isn't. It will parse the String as an int if the String is a number. And what a number is depends partially on the radix, but, when you don't designate one, the radix is 10 (i.e. normal decimal numbers).