Need Urgent help parseInt and parseFloat problem in code need help plz

I am having two classes Temperature and Converter these classes are infact two different files.
The classes are as follows:-
--------------------------------------------------------------------------
public class Temperature
{
private double Fahrenheit,Celsius;
public double Fahren2Cels(double Fahren)
{
Celsius = ((Fahren * (9 / 5)) + 32);
return Celsius;
}
public double Cels2Fahren(double Cels)
{
Fahrenheit = ((Cels - 32) * (5 / 9));
return Fahrenheit;
}
}

--------------------------------------------------------------------------
import java.io.*;
import java.lang.*;
public class Converter
{
static Temperature t1 = new Temperature();
public static void main(String args[])
{
System.out.println("Menu:");
System.out.println("1. Convert Fahrenheit to Celsius.");
System.out.println("2. Convert Celsius to Fahrenheit.");
BufferedReader br2 = new BufferedReader(new InputStreamReader(System.in));
int ch = Integer.parseInt(br2);
switch (ch)
{
case 1:
System.out.println("Enter the temperature in Fahrenheit.");
BufferedReader br1 = new BufferedReader(new InputStreamReader(System.in));
double value = Double.parseDouble(br1);
double ans = t1.Fahren2Cels(value);
System.out.println("The ans is "+ans);
break;
/*Rest code yet to be developed*/
default:
break;
}
}
}
--------------------------------------------------------------------------
Temperature class compiles well, but while compiling Converter the compile time error are as follows:-
--------------------------------------------------------------------------
D:\Program Files\Java\jdk1.7.0\bin>javac Converter.java
Converter.java:14: cannot find symbol
symbol : method parseInt(java.io.BufferedReader)
location: class java.lang.Integer
int ch = Integer.parseInt(br2);
^
Converter.java:20: method parseDouble in class java.lang.Double cannot be applied to given types
required: java.lang.String
found: java.io.BufferedReader
double value = Double.parseDouble(br1);
^
2 errors
--------------------------------------------------------------------------
Someone plz help me its urgent

• Integer.parseInt(BufferedReader) doesn't exist.
• Double.parseDouble(BufferedReader) doesn't exist.
• What does exist is:

Integer parseInt(java.lang.String)

Double parseDouble(java.lang.String))

Question: why are you trying to turn the double's result into into int?

Luck,
CJSL

I did the necessary changes both the classes compiled successfully but now there is a runtime exception pls go through:-
--------------------------------------------------------------------------
public class Temperature
{
private double Fahrenheit,Celsius;
public double Fahren2Cels(double Fahren)
{
Celsius = ((Fahren * (9 / 5)) + 32);
return Celsius;
}
public double Cels2Fahren(double Cels)
{
Fahrenheit = ((Cels - 32) * (5 / 9));
return Fahrenheit;
}
}
--------------------------------------------------------------------------
import java.io.*;
import java.lang.*;
public class Converter
{
static Temperature t1 = new Temperature();
public static void main(String args[])
{
System.out.println("Menu:");
System.out.println("1. Convert Fahrenheit to Celsius.");
System.out.println("2. Convert Celsius to Fahrenheit.");
BufferedReader br2 = new BufferedReader(new InputStreamReader(System.in));
int ch = Integer.parseInt(br2.toString());
switch (ch)
{
case 1:
System.out.println("Enter the temperature in Fahrenheit.");
BufferedReader br1 = new BufferedReader(new InputStreamReader(System.in));
double value = Double.parseDouble(br1.toString());
double ans = t1.Fahren2Cels(value);
System.out.println("The ans is "+ans);
break;
default:
break;
}
}
}
--------------------------------------------------------------------------
D:\Program Files\Java\jdk1.7.0\bin>java Converter
Menu:
1. Convert Fahrenheit to Celsius.
2. Convert Celsius to Fahrenheit.
Exception in thread "main" java.lang.NumberFormatException: For input string: "j
ava.io.BufferedReader@173a10f"
at java.lang.NumberFormatException.forInputString(Num berFormatException.
java:65)
at java.lang.Integer.parseInt(Integer.java:484)
at java.lang.Integer.parseInt(Integer.java:519)
at Converter.main(Converter.java:12)
--------------------------------------------------------------------------
Pls provide me more help..........

br1.toString() ?, how can it be...

Then what should be done 2 accept a comand line input and apply it in a switch case for the perticular case to be executed.

use method like readLine in bufferReader to read a line of string
and
catch IOException .. NumberFormatException

Thanks a lot it worked.

No answer it produces 0.0 as the answer where is the problen pls check the code:-
--------------------------------------------------------------------------
public class Temperature
{
private double Fahrenheit,Celsius;
public double Fahren2Cels(double Fahren)
{
Celsius = ((Fahren -32) * 5 / 9);
return Celsius;
}
public double Cels2Fahren(double Cels)
{
Fahrenheit = ((Cels * (9 / 5)) + 32);
return Fahrenheit;
}
}
--------------------------------------------------------------------------
import java.io.*;
import java.lang.*;
public class Converter
{
static Temperature t1 = new Temperature();
public static void main(String args[])
{
System.out.println("Menu:");
System.out.println("1. Convert Fahrenheit to Celsius.");
System.out.println("2. Convert Celsius to Fahrenheit.");
try
{
BufferedReader br2 = new BufferedReader(new InputStreamReader(System.in));
int ch = Integer.parseInt(br2.readLine());
switch (ch)
{
case 1:
System.out.println("Enter the temperature in Fahrenheit.");
BufferedReader br1 = new BufferedReader(new InputStreamReader(System.in));
double value = Double.parseDouble(br1.readLine());
double ans = t1.Fahren2Cels(value);
System.out.println("The ans is "+ans);
break;
default:
break;
}
}catch(Exception e)
{
System.out.println("The Exception is"+e);
}
}
}
--------------------------------------------------------------------------
D:\Program Files\Java\jdk1.7.0\bin>java Converter
Menu:
1. Convert Fahrenheit to Celsius.
2. Convert Celsius to Fahrenheit.
1
Enter the temperature in Fahrenheit.
103
The ans is 0.0
--------------------------------------------------------------------------
What is the problem i am not getting anyone with a sollution pls.

The Fahren to Cels works fine for me? Sure you compiled the latest version of your code?

Quote:

---

Menu:
1. Convert Fahrenheit to Celsius.
2. Convert Celsius to Fahrenheit.
1
Enter the temperature in Fahrenheit.
103
The ans is 39.44444444444444

---

Luck,
CJSL

Thans i was compiling the wrong file.

Hey does any one know when we write an interface in a file what the files extension is suppose to be.

for public interface XXX
XXX.java should be the file name