Get a certain row in a string.

Say I have a string, for example:

String s = "abcdefgh\n" +
"ijklmno\n" +
"pqrstuvwxyz";

and I know the character position in the string, how can i get the specific row where that character is, and store it in a string?
For example, say I know that the character is at position 13 (the 'm'), how can I get the second row?

Actually, from a string variable point of view, a string is just a string. It does know about rows. The "/n" is just another part of the string. If you lay it out, it would look like:

Code:

---

String s = "abcdefgh\nijklmno\npqrstuvwxyz";

---

You can use various combinations of string methods (indexOf, substring, etc) to obtain what you want, using "/n" as a token/separator. Also, you may want to investigate regular expressions (regex), but I have no experience with that.
String API (methods):
String (Java Platform SE 6)
Regular Expressions:
Introduction (The Java™ Tutorials > Essential Classes > Regular Expressions)

Luck,
CJSL

You could always split your String into an array of Strings with each item in the array being a row. To do this, simply use the newline char as your regex for splitting. Don't forget to use double backslashes or it won't work:

Code:

---

  public static void main(String[] args)
  {
    String s = "abcdefgh\n" +
    "ijklmno\n" +
    "pqrstuvwxyz";
   
    String[] rows = s.split("\\n");
    System.out.println(Arrays.toString(rows));
  }

---

Quote:

---

Originally Posted by Fubarable

You could always split your String into an array of Strings with each item in the array being a row. To do this, simply use the newline char as your regex for splitting. Don't forget to use double backslashes or it won't work:

Code:

---

  public static void main(String[] args)
  {
    String s = "abcdefgh\n" +
    "ijklmno\n" +
    "pqrstuvwxyz";
   
    String[] rows = s.split("\\n");
    System.out.println(Arrays.toString(rows));
  }

---

---

Yes, I'm aware of how the split function works, but the problem is, I need to pick out exactly what row the character whose position is n is on.
I guess I could do something like:

Code:

---

    String s = "abcdefgh\nijklmno\npqrstuvwxyz";
    int charPos = 15;
    String[] sArr = s.split("\\n");
    int row;
    for(int i=0;i<sArr.length;i++) {
      int count = 0;
      for(int j=0;j<=i;j++) { //loop through all rows before and including this one, checking the sum of their length
        count+=sArr[j].length+1; //the +1 compensating for the \n
      }
      count--; //Character position starts at 0, length starts at 1
      if(count>=charPos) { //if we've went past the position of the character we want, we know that it must be located on the current row
        row = i;
        break;
      }
    }

---

But, well... It just seems like an ugly solution. Isn't there any better way to do this?
Also, I haven't tested the code, maybe it works, maybe not. Will have to try.