[SOLVED] Arrays of Objects with Subscripts

[Sidmyre]

Hi there, im trying to figure out how to how to display a list of the first names that are in an array of objects with subscripts, as a loop.

shown below

		Employee names[] = new Employee[5];

		names[0].setFirstName("John");
		names[0].setLastName("doe");
		names[0].setID("1234");

		names[1].setFirstName("Mary");
		names[1].setLastName("berry");
		names[1].setID("2345");

		names[2].setFirstName("Chris");
		names[2].setLastName("bliss");
		names[2].setID("3456");

		names[3].setFirstName("Angela");
		names[3].setLastName("Jolie");
		names[3].setID("4567");

		names[4].setFirstName("Marky");
		names[4].setLastName("mark");
		names[4].setID("5678");

//This is what ive tried but it does not work
for (int i = 0; i < names.length; i++)
	 System.out.println(names[i].getFirstName());

Edit: this accesses another file Employee, with methods already.

[Fubarable]

Does this Employee class have a toString() method? If so, you might be able to display it quite simply:

for (int i = 0; i < names.length; i++)
{
  System.out.println(names[i]);
}

[Sidmyre]

Does this Employee class have a toString() method? If so, you might be able to display it quite simply:

for (int i = 0; i < names.length; i++)
{
  System.out.println(names[i]);
}

yea

public String toString()
	{
		return 	firstName + " " + lastName + " (" + id + ")";
	}

although, when I do

for (int i = 0; i < names.length; i++)
{
  System.out.println(names[i]);
}

I get " Exception in thread "main" java.lang.NullPointerException"

[Fubarable]

then your code has a bug and the names object is null here. you have to fix this.

In your code above, I don't see you creating any "new" Employee objects, just a new array. Please know that when you create an array of objects (as opposed to an array of primitive such as ints), you have to create a new object for each item in the array.

[Sidmyre]

ahhh I see what you did there ;P

got it

  Employee[] names = new Employee[5];
  names[0] = new Employee("John", "doe", "1234");
  names[1] = new Employee("Mary","berry", "2345");
  names[2] = new Employee("Chris", "bliss", "3456");
  names[3] = new Employee("Angela", "Jolie", "4567");
  names[4] = new Employee("Marky", "mark", "5678");

gracias

[Fubarable]

Good job. So hopefully now it works. Oh, and my girlfriend's name is spelled "Angelina", not "Angela".