Help me with create a 2D Maze in Java

[hnam31190]

HI.
I am a newbie with Java. And i am doing a project by create a maze in 2D Maze.
I am confusing about writing a code for the Save and Retrieve button. (The retrieve button will load a file (type: *.maze) which is included in the zip file.)
The Retrieve and Save button will load an save the tube maze via binary files.
Anyone can help me write the code for retrieve button. (In the class: TubeSearcher). And the we can test this button by trying retrieve the sample.maze file in the zip file.

Thanks a lot
Best regards

(sorry when I not write a code here cause it's a lot of class in the zip file)

[Norm]

YOU need to solve your problem one small step at a time. First write the save and load methods separately then write the GUI that calls those methods. What structures are you using to hold the maze in your program?
Why do you want to save the data as binary vs as text?

[hnam31190]

Well, for the binary vs text file. My project required to load and save content via binary file.
And also the structures will be using the recursion (for find the part)which I am studying now.
Thanks Norm

[hnam31190]

Can you tell me what did I do wrong here? for retrieve

private void retrieve() {
		try{
			JFileChooser fc = new JFileChooser();;
		
		int returnVal = fc.showOpenDialog(TubesSearcher.this);
		File file = fc.getSelectedFile();
		
		if (returnVal == JFileChooser.APPROVE_OPTION) {

			FileReader fReader = new FileReader(file);
			BufferedReader reader = new BufferedReader(fReader);
			
			
		}//end of If
		}
		catch(java.io.IOException IOexc){
			System.out.println("Cannot read from file");
		}

		catch(java.lang.NullPointerException NPexc){
			System.out.println("NullPointerException occurs");
		}
	}

[Norm]

Can you tell me what did I do wrong here

Not without you telling me what the code is supposed to do and what it is doing that you don't like.
Do you get an error or what?

Its better to use a printStackTrace() call in caught exceptions. There is often important information included in the message showen.